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vichka [17]
3 years ago
15

Two plumbing companies charge money for each hour of work, plus a one-time fee

Mathematics
1 answer:
Rama09 [41]3 years ago
4 0

Answer:

a. A Plus Plumbing company charges $60 per hour and $80 as one-time fee

b. Quality Plumbing company charges $50 per hour and $150 as one-time fee

c. Yes, they can charge the same amount of $500 for 7 hours of work.

Step-by-step explanation:

Write the linear functions representing both companies charges

<u>A Plus Plumbing Company:</u>

Slope =\dfrac{320-140}{4-1}=\dfrac{180}{3}=60

Equation:

y-140=60(x-1)\\ \\y=60x-60+140\\ \\y=60x+80

<u>Quality Plumbing Company:</u>

Slope =\dfrac{200-150}{1-0}=\dfrac{50}{1}=50

Equation:

y-150=50(x-0)\\ \\y=50x+150

a. A Plus Plumbing company charges $60 per hour and $80 as one-time fee

b. Quality Plumbing company charges $50 per hour and $150 as one-time fee

c. Suppose they charge the same amount of money, then

60x+80=50x+150\\ \\60x-50x=150-80\\ \\10x=70\\ \\x=7

Yes, they can charge the same amount of \$(50\cdot 7+150)=\$500 for 7 hours of work.

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Twice a number increased by 3 is 45. What is the number?
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3 years ago
Two stores sell a certain product. Store A has 45% of the sales, 3% of which are of defective items, and store B has 55% of the
Mumz [18]

Answer:

Probability = 0.0355

Step-by-step explanation:

Given

Stot A:

Sales = 45\%

Defective = 3%

Store B

Sales = 55\%

Defective = 4%

Required

Determine the probability a product received is defective.

First, we calculate the probability that the defective product is from store A

Probability = P(Sales) * P(Defective)

P_A = 45\% * 3\%

Convert to decimals

P_A= 0.45 * 0.03

P_A= 0.0135  

Next, we calculate the probability that the defective product is from store B

P_B= 55\% * 4\%

P_B= 0.55 * 0.04

P_B= 0.022

The product may come from either stores.

So, the probability of having a defective product is:

Probability = P_A + P_B

Probability = 0.0135 + 0.022

Probability = 0.0355

4 0
3 years ago
Someone please help. thanks!
kow [346]

Answer:  (-0.61, 5.85) and (-2.72, 3.04)

<u>Step-by-step explanation:</u>

y = 2x² + 8x + 10

y = -x² - 2x + 5

Use substitution method to get:   2x² + 8x + 10 =  -x² - 2x + 5

Move everything to one side and 0 on the other: 3x² + 10x + 5 = 0

Use the quadratic formula to solve for x: \dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\dfrac{-(10)\pm \sqrt{(10)^2-4(3)(5)}}{2(3)}\\\\\\.\ =\dfrac{-10\pm \sqrt{100-60}}{6}\\\\\\.\ =\dfrac{-10\pm \sqrt{40}}{6}\\\\\\.\ =\dfrac{-10\pm 2\sqrt{10}}{6}\\\\\\.\ =\dfrac{-5\pm \sqrt{10}}{3}

x₁ = -0.61                                    x₂ = -2.72

Next, input the x-values to solve for y:

y₁ = -x² - 2x + 5                          y₂ = -x² - 2x + 5

   = -(-0.61)² - 2(-0.61) + 5              = -(-2.72)² - 2(-2.72) + 5

   =  -0.37 + 1.22 + 5                     = -7.40 + 5.44 + 5

   =  5.85                                       = 3.04


6 0
3 years ago
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