All categories

3 years ago

And a fruit basket there are nine bananas for apples and three plums

Mathematics

1 answer:

nevsk [136]3 years ago

4 0

9:4
3 to 4
hope it helps;)

You might be interested in

Hello I would like some help with this problem if possible

alexdok [17]

Answer: fifty four degrees (54)

Step-by-step explanation: Using the law of sines you'd multiply both sides by b then plug in the known values... sin(B)= 9/11xsin(80degrees). Then, you'd evaluate to find B and after solving you'd reach 54

5 0

3 years ago

5. After paying a tax of 8 palsa per rupee a man saves Rs. 18,400 per month Then his monthly income is 2 Points) 20,000

Hunter-Best [27]

Answer:

92% of Income is Rs 18400

Step-by-step explanation:

I = 18400/.92 = Rs 20000

8 0

2 years ago

Please Help Me! [99 points]

Kobotan [32]

I am not sure but i think is a

4 0

3 years ago

Read 2 more answers

Which variable expression matches the word phrase? Column A Column B

erik [133]

1. the sum of 12 and the quotient of 9 and a number

The responder's answer is not given but it can be 12 + (9 / n)

2. the difference of 12 and the product of 9 and a number

The responder's answer would be c. 12 – 9y

3. the difference of 12 and the quotient of 9 and a number

The responder's answer would be b. 12 – (9 ÷ y)

4. 12 more than quotient of a 9 and number

The responder's answer would be a. 12 + (9 ÷ y)

4 0

3 years ago

A shoe manufacturer was investigating the weights of men's soccer cleats. He felt that the weight of these cleats was less than

aleksklad [387]

Answer:

The conclusion is that the researcher was correct

Step-by-step explanation:

From the question we are told that

The sample size is $n = 13$

The sample mean is $\= x = 9.63$

The standard deviation is $s = 0.585$

The significance level is $\alpha = 0.05$

The Null Hypothesis is $H_o : \mu = 0$

The Alternative Hypothesis is $H_a = \mu < 10$

The test statistic is mathematically represented as

$t = \frac{\= x - \mu }{\frac{s}{\sqrt{n} } }$

Substituting values

$t = \frac{9.63 - 10 }{\frac{0.585}{\sqrt{13} } }$

$t = - 2.280$

Now the critical value for $\alpha$ is

$t_{\alpha } = 1.645$

This obtained from the critical value table

So comparing the critical value of alpha and the test value we see that the test value is less than the critical value so the Null Hypothesis is rejected

The conclusion is that the researcher was correct

6 0

3 years ago