You have -3y=-2x+6 divide both sides by -3 and you'll get:<span><span><span>−3y</span><span>−3</span></span>=<span><span>−2x</span><span>−3</span></span>−<span>63
</span></span>its y=2/3x-2
D. (xy2 + 3z14)(x2y4 – 3xy2z14 + 9z28
Find m∠BOC, if m∠MOP = 110°.
Answer:
m∠BOC= 40 degrees
Step-by-step explanation:
A diagram has been drawn and attached below.
- OM bisects AOB into angles x and x respectively
- ON bisects ∠BOC into angles y and y respectively
- OP bisects ∠COD into angles z and z respectively.
Since ∠AOD is a straight line
x+x+y+y+z+z=180 degrees

We are given that:
m∠MOP = 110°.
From the diagram
∠MOP=x+2y+z
Therefore:
x+2y+z=110°.
Solving simultaneously by subtraction

x+2y+z=110°.
We obtain:
x+z=70°
Since we are required to find ∠BOC
∠BOC=2y
Therefore from x+2y+z=110° (since x+z=70°)
70+2y=110
2y=110-70
2y=40
Therefore:
m∠BOC= 40 degrees
The answer is B. I hope this helped.
When an equation is balanced, the different ways that the
simulation indicates are as follows:
- Happy Face appears
- The scales are balanced
- Pictures show same kind of atoms in reactants and products
- Pictures show same number of atoms in reactants and
products