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anygoal [31]
3 years ago
7

5 consecutive integers whose sum is -155

Mathematics
1 answer:
nekit [7.7K]3 years ago
5 0

Answer:

-29, -30, -31, -32, -33

Step-by-step explanation:

add them together

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Juli2301 [7.4K]

Answer:

I believe the answer is 540* because

Step-by-step explanation:

we start with the fractions, we have 3/4 and 1/4 which makes a whole, to make it easier i added that to 329 to get 330. Then i added 330 to 210 to get 540.

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On Earth day, a local community wants to distribute 800 flyers, 300 banners, and 250 badges to volunteers in packets containing
steposvetlana [31]

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800 flyersOn Earth day, a local community wants to distribute 800 flyers, 300 banners, and 250 badges to volunteers in packets containing the three items. What is the greatest number of packets that can be made using all these items if each type of item is equally distributed among the packets?

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ryzh [129]
330 page/(3/4 Hour):==> 330 : 3/4
To solve this division you have to MULTIPLY the 1st term by the reciprocal of the 2nd (the reciprocal of 3/4 is 4/3), so

330 x 4/3 = (330x4)/3 = 440
330 pages were read in 3/4 Hour (given)  & in 1 hour. could be read

3 0
3 years ago
What are the roots of this equation? x2-4x+9=0
zysi [14]

Considering the definition of zeros of a function, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

<h3>Zeros of a function</h3>

The points where a polynomial function crosses the axis of the independent term (x) represent the so-called zeros of the function.

In summary, the roots or zeros of the quadratic function are those values ​​of x for which the expression is equal to 0. Graphically, the roots correspond to the abscissa of the points where the parabola intersects the x-axis.

In a quadratic function that has the form:

f(x)= ax² + bx + c

the zeros or roots are calculated by:

x1,x2=\frac{-b+-\sqrt{b^{2}-4ac } }{2a}

<h3>This case</h3>

The quadratic function is f(x) = x² + 4x +9

Being:

  • a= 1
  • b= 4
  • c= 9

the zeros or roots are calculated as:

x1=\frac{-4+\sqrt{4^{2}-4x1x9 } }{2x1}

x1=\frac{-4+\sqrt{16-36 } }{2x1}

x1=\frac{-4+\sqrt{-20 } }{2x1}

and

x2=\frac{-4-\sqrt{4^{2}-4x1x9 } }{2x1}

x2=\frac{-4-\sqrt{16-36 } }{2x1}

x2=\frac{-4-\sqrt{-20} }{2x1}

If the content of the root is negative, the root will have no solution within the set of real numbers. Then \sqrt{-20} has no solution.

Finally, the zeros of the quadratic function f(x) = x² + 4x +9 do not exist.

Learn more about the zeros of a quadratic function:

brainly.com/question/842305

brainly.com/question/14477557

#SPJ1

6 0
1 year ago
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