Answer:
768 bugs
Step-by-step explanation:
You can rewrite this problem as a function as time where the bug population is f(x), and x is the number of days since the start.
f(x)=6*2^(x/5)
Here, the 6 represents the number of bugs that you start with, the two shows that they double every day, and the /5 shows that they double every 5 days.
By plugging in 35, you get 6*2^7, which is 768.
Answer:
In disguise right arrow In Standard Form a, b and c
x2 = 3x − 1 Move all terms to left hand side x2 − 3x + 1 = 0 a=1, b=−3, c=1
2(w2 − 2w) = 5 Expand (undo the brackets),
and move 5 to left 2w2 − 4w − 5 = 0 a=2, b=−4, c=−5
z(z−1) = 3 Expand, and move 3 to left z2 − z − 3 = 0 a=1, b=−1, c=−3
Step-by-step explanation:
sorry it took so long
Answer:
0.9544
Step-by-step explanation:
P(-2 < Z < 2) means that Z has mean 0 and standard deviation 2.
P(−2 < Z < 2) = F(2) - F(-2)
Using the Z - table,
F(2) = 0.9772
and F(-2) = 0.0228
Thus,
P(−2 < Z < 2) = 0.9772 - 0.0228 = 0.9544
This means that data within two standard deviation is 95%.
Answer: 3.75
Step-by-step explanation:
