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klio [65]
3 years ago
15

HELP NOW!!!!

Mathematics
1 answer:
mrs_skeptik [129]3 years ago
7 0

Answer:

Refer to Image.

3 went 0 to 5 times

2 went 6 to 10 times

3 went 11 to 15 times

1 went 16 to 20 times

3 went 21 to 25 times

Step-by-step explanation:

When making a histogram, it's good practice to first gather all the frequencies of each number.

1 - 1

3 - 1

4 - 1

6 - 1

10 - 1

11 - 2

12 - 1

16 - 1

20 - 2

22 - 1

Now that we have the total number of frequencies of each number, we can then combine the frequencies for each age range.

0 - 5:  3

6 - 10: 2

11 - 15: 3

16 - 20: 1

21 - 25: 3

The histogram shows that out of the 12 visitors.

3 went 0 to 5 times

2 went 6 to 10 times

3 went 11 to 15 times

1 went 16 to 20 times

3 went 21 to 25 times

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Simplify: 3 5 power x 3-2power
natta225 [31]

Answer:

3 to the power of 5 is 243 and 3 to the power of 2 is 9 and

243 x 9 is 2187

Step-by-step explanation:

7 0
3 years ago
The nth term of this sequence is ansquared+by+c<br> 1,11,27,49 <br> Find the values of a b and c
stiv31 [10]

Answer:

The values of a, b and c are:

  • a = 3
  • b = 1
  • c = -3

Step-by-step explanation:

Step 1:

First Confirm the sequence is quadratic by finding the second difference.

Sequence = 1,11,27,49

1st difference:

  • 11-1=10
  • 27-11=16
  • 49-27=22

2nd difference:

  • 16-10=6
  • 22-16=6

Step 2:

Just divide the second difference by 2, you will get the value of a.

6 ÷ 2 = 3

So the first term of the nth term is 3n^{2}

Step 3: Next, substitute the number 1 to 5 into  3n^{2}

n = 1,2,3,4,5

3n² = 3,12,27,48,75

Step 4:

Now, take these values (3n²) from the numbers in the original number sequence and work out the nth term of these numbers that form a linear sequence.

n = 1,2,3,4,5

3n² = 3,12,27,48,75

Differences:

1 - 3 = -2

11 - 12 = -1

27 - 27 = 0

49 - 48 = 1

Now the nth term of these differences (-2,-1,0,1) is (n - 1) - 2.

so b = 1, and c = -3

Step 5: Write down your final answer in the form an² + bn + c.

3n² + (n - 1) -2

= 3n² + n - 1 - 2

= 3n² + n - 3

Therefore, the values of a, b and c are:

  • a = 3
  • b = 1
  • c = -3
4 0
3 years ago
Perrie invests £25000 for 3 years in a saving account. She gets 2.7% per annum compound interest. Calculate the total amount of
aleksandr82 [10.1K]

Answer:

I (interest) = £ 2,080.17

Step-by-step explanation:

Perrie invests £25000 for 3 years in a saving account. She gets 2.7% per annum compound interest. Calculate the total amount of interest perrie will get after 3 years.

To solve the above question, we would use the Periodic compound interest formula

A = P(1 + r) ^t

Where P = Principal = £25000

r = Interest rate = 2.7 % = 0.027

t = time in years = 3 years

Hence:

A = £25,000( 1 + 0.027)³

A = £27,080.17

A = P + I where

P (principal) = £ 25,000.00

I (interest) = £27,080.17 - £ 25,000.00

I (interest) = £ 2,080.17

The total amount of interest perrie will get after 3 years is £ 2,080.17

3 0
2 years ago
A t statistic was used to conduct a test of the null hypothesis H0: µ = 11 against the alternative Ha: µ ? 11, with a p-value eq
Andrews [41]

Answer:

e. A 98% confidence level.

Step-by-step explanation:

Confidence level represents the percentage of probability as well as certainty that the confidence interval would contain the true population parameter when a random sample is selected many times.

Confidence intervals provide us with an upper and lower limit surrounding the sample mean, and within this interval we can then be confident we have captured the population mean.

From the information given above, to solve this question, we need to find the largest level of confidence for which the confidence interval will NOT contain 11.

In order to do this, we must produce the confidence interval.

Producing the confidence interval, for H0: µ = 11 against Ha: µ ?

11 would definitely produce a P-value less than (<) 0.042. The reason being that we can reject null hypothesis and confidence interval will not contain the value 11.

From given options above we have values as 0.10, 0.08, 0.04, 0.03, and 0.02.

Out of all these values, p value = 0.042 < 0.10 and 0.042<0.08

Therefore,the largest level of confidence for which the confidence interval will NOT contain 11 is 98% confidence level.

5 0
3 years ago
11.23 grams in word form
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