1) D
(2/9) x=24
2) C
6x4=24
24=w
W=1/4(6)
3) A
67=9n
67=9n-2
9n-2=67
4) D
C+2x+x-3=56
4x=59
X=14.75
Katie payed 14.75
5) 91
Explanation: divide 18 by two and you get 9. When you add six and seven you carry on so those are your numbers. After you add you get your consecutive numbers, 91 and 92. 91 is the smallest so that is your answer
6)-18
Explanation: c+c+2=-34
2c+2-34
2x=-36
X=-18
18 is your answer
7) 17
Explanation: divide 22 is half. This is 11. 11+6=17. 17 is your answer
8)D
9)A
11-3 =x
However that isn’t an option so I would suggest to choose 3
10)D
4(17-n)=64
The answer is 17 hoped this helped
The average velocity of the particle in the time interval between 3s and 5s is 20 ms⁻¹ and its instantaneous velocity at 4s is 20 ms⁻¹.
How to determine average velocity and instantaneous velocity?
Average velocity is defined as the body's overall displacement divided by its time of motion. While instantaneous velocity is defined as a body's speed at a certain instant in time, or its displacement at that instant. When the velocity is constant, average and instantaneous velocities will equalize at just one condition.
The definition of instantaneous velocity is the rate of change of position over a relatively brief time period (almost zero). Simply said, the speed of an object at that precise moment. The definition of instantaneous velocity is "The velocity of an item in motion at a certain point in time." The instantaneous velocity of an object may be equal to its standard velocity if it has uniform velocity.
Mathematically, average velocity = [s(t₂) - s(t₁)]/[t₂ - t₁]
Instantaneous velocity at time, t is = (ds/dt) at time = t
Given, the displacement for the particle is given by s = 3t² - 4t + 5
Time interval, t₁ = 5s and t₂ = 3s;
Using formula in literature, average velocity of the particle in the time interval between 3s and 5s is:
Average velocity = (s(5) - s(3))/(5 - 3) = (60 - 20)/2 = 20 ms⁻¹
Instantaneous velocity at t = 4 is ds/dt at that time-frame:
Now, v = ds/dt = 6t -4
Now, v(4) = 6(4) - 4 = 20 ms⁻¹
The average velocity of the particle in the time interval between 3s and 5s is 20 ms⁻¹ and its instantaneous velocity at 4s is 20 ms⁻¹.
To learn more about this, tap on the link below:
brainly.com/question/2234298
#SPJ9
Hey there!
To solve this expression, you must follow your orders of operations or PEMDAS (Parenthesis, Exponents, Multiplication and Division, Addition and Subtraction).
In the case of <span>5[3(14.5+7)-3]-7.4, you not only have parenthesis, but you also have brackets. To start, you would first simplify what is in the parenthesis:
</span><span>5[3(14.5+7)-3]-7.4
5[3(21.5)-3]-7.4
Now, simplify what is in the bracket, starting by multiplying 3(21.5) since multiplication comes before addition and subtraction:
</span><span>5[3(21.5)-3]-7.4
5[64.5-3]-7.4
5[61.5]-7.4
Now, multiply 5*61.5 since multiplication comes next:</span>
<span>5[61.5]-7.4
307.5-7.4
And finally, subtract what is left since it is your final operation remaining to get 300.1 as your final answer.
Hope this helps and have a marvelous day!
</span>
