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viktelen [127]
2 years ago
14

Choose the correct converse.

Mathematics
1 answer:
Lady bird [3.3K]2 years ago
6 0
Dddddddddddddddddddd
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Expand the following.<br> (3x + 2)2<br> A.9x2+6x+4<br> B.9x2+4<br> C.3x2+4<br> E.9x2+12x+4
PolarNik [594]

Step-by-step explanation:

E

working ;

(3x+2)^2

*Apply Perfect Square Formula : (a+b) =a^2+2ab+b^2

a = 3x,b = 2

(3x)^2 + 3x.2+2^2

finally Answer is:

= 9x^2 + 12x +4

5 0
2 years ago
Write Y+2=1/3x in standard form
solong [7]

The standard form of a line is in the form

Ax + By = C

A, B and C are integers, and A is positive. Let's start with multiplying the whole equation by 3 to get rid of denominators:

3y+6=x

Subtract 3y from both sides:

6=x-3y

Which of course is equivalent to

x-3y=6

Which is the standard form, given the coefficients A=1, B=-3, C=6.

4 0
3 years ago
22+(30-4) ÷2 And 18+(22-4) ÷6
schepotkina [342]

22 + (30 - 4) divided by 2

30 - 4 = 26

26/2 = 13

22 + 13 = 35

35

18 + (22 - 4) divided by 6

22 - 4 = 18

18 divided by 6 = 3

18 + 3 = 21

21

6 0
3 years ago
Read 2 more answers
Simplify<br> 7^2x^-3y/49x^-3y^-2
olya-2409 [2.1K]
\frac{7^2x^{-3}}{49x^{-3} y^{-2}} \\ \\  \frac{49x^{-3}y}{49x^{-3}y^{-2}} \\ \\  \frac{49x^{-3}y}{49x^{-3} \times  \frac{1}{y^2} } \\ \\  \frac{49x^{-3}y}{ \frac{49x^{-3}}{y^2} } \\ \\ 49x^{-3} y \times  \frac{y^2}{49x^{-3}} \\ \\  \frac{x^{-3}}{x^{-3}} yy^2 \\ \\ 1 \times yy^2 \\ \\ yy^2 \\ \\ y^3 \\ \\

The answer is: y^3.
4 0
3 years ago
Read 2 more answers
Verify and show work<br><br> csc x - cos x • cot x = sin x
Vladimir79 [104]

Answer:   The answer is (d) ⇒ cscx = √3

Step-by-step explanation:

∵ sinx + (cotx)(cosx) = √3

∵ sinx + (cosx/sinx)(cosx) = √3

∴ sinx + cos²x/sinx = √3

∵ cos²x = 1 - sin²x

∴ sinx + (1 - sin²x)/sinx = √3 ⇒ make L.C.M

∴ (sin²x + 1 - sin²x)/sinx = √3

∴ 1/sinx = √3

∵ 1/sinx = cscx

∴ cscx = √3

5 0
2 years ago
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