PLS HELP!! 10 POINTS!! Which part is NOT included in an experiment? Independent variable / Control / Data / Proof

The equilibrium constant, Kp, for the reaction H2(g) + I2(g) → 2HI(g) is 55.2 at 425°C. A rigid cylinder at that temperature con

Fiesta28 [93]

Answer: No, the reverse reaction must proceed to establish equilibrium.

Explanation:

$K_p$ is the constant of a certain reaction at equilibrium while $Q_p$ is the quotient of activities of products and reactants at any stage other than equilibrium of a reaction.

For the given chemical reaction:

$H_2(g)+I_2(g)\rightleftharpoons 2HI(g)$

The expression of $Q_p$ for above equation follows:

$Q_p=\frac{(p_{HI})^2}{p_{H_2}\times p_{I_2}}$

We are given:

$p_{HI}=1.055atm\\p_{H_2}=0.127atm\\p_{I_2}=0.134atm$

Putting values in above equation, we get:

$Q_p=\frac{(1.055)^2}{0.127\times 0.134}=65.41$

We are given:

$K_p=55.2$

There are 3 conditions:

When $K_{p}>Q_p$ ; the reaction is product favored.
When $K_{p}$ ; the reaction is reactant favored.
When $K_{p}=Q_p$ ; the reaction is in equilibrium.

As, $Q_p>K_p$ , the reaction will be favoring reactant side or the reaction must proceed in the reverse direction.

Hence, no, the reverse reaction must proceed to establish equilibrium.

6 0

3 years ago

over a 12.3 minuete period 5.13 E-3 moles of F2 gas effuses from a contaier. How many moles of CH4 gas could effuse from from th

Aleonysh [2.5K]

Answer : The moles of methane gas could be, $7.90\times 10^{-3}mol$

Solution :

According to the Graham's law, the rate of effusion of gas is inversely proportional to the square root of the molar mass of gas.

$R\propto \sqrt{\frac{1}{M}}$

or,

$(\frac{R_1}{R_2})=\sqrt{\frac{M_2}{M_1}}$

$[\frac{(\frac{n_1}{t_1})}{(\frac{n_2}{t_2})}]=\sqrt{\frac{M_2}{M_1}}$

where,

$R_1$ = rate of effusion of fluorine gas

$R_2$ = rate of effusion of methane gas

$n_1$ = moles of fluorine gas = $5.13\times 10^{-3}mol$

$n_2$ = moles of methane gas = ?

$t_1=t_2$ = time = 12.3 min (as per question)

$M_1$ = molar mass of fluorine gas = 38 g/mole

$M_2$ = molar mass of methane gas = 16 g/mole

Now put all the given values in the above formula 1, we get:

$[\frac{(\frac{5.13\times 10^{-3}mol}{12.3min})}{(\frac{n_2}{12.3min})}]=\sqrt{\frac{16g/mole}{38g/mole}}$

$n_2=7.90\times 10^{-3}mol$

Therefore, the moles of methane gas could be, $7.90\times 10^{-3}mol$

8 0

3 years ago

Pls help.

stepan [7]

Answer:

c or d

Explanation:

it says it was playing classic music

7 0

2 years ago

My greatest influence on career pathing right now is___________

spayn [35]

Answer:

My greatest influence on career pathing right now is minecraft hardcore.Track and strand choice.

6 0

3 years ago

Telephone signals are often transmitted over long distances by microwaves. what is the frequency of microwave iradiation with a

Alborosie

c = speed of light = 3.00 x 10^5 km/s = 3.00 x 10^8 m/s
Î» = wavelength of the microwave radiation = 3.50 cm = 0.035 m
f = frequency (in Hertz) = to be determined
f = c/Î» = 3.00 x 10^8 m/s / 0.035 m
f = 8.57 x 10^9 Hz Frequency

6 0

4 years ago

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