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Aleksandr-060686 [28]
3 years ago
7

Telephone signals are often transmitted over long distances by microwaves. what is the frequency of microwave iradiation with a

wavelength of 3.50 cm
Chemistry
2 answers:
masha68 [24]3 years ago
7 0
The computation for this problem would be:

The formula that we will be using is: f = c/λ

Where:

c = speed of light = 3.00 x 10^5 km/s convert it to meters, so: 3.00 x 10^8 m/s 

λ = wavelength of the microwave radiation = 3.50 cm convert this to meters, so: 0.035 m 

f = frequency (in Hertz) 
f = c/λ

= 3.00 x 10^8 m/s / 0.035 m 

f = 8.57 x 10^9 Hz Frequency 
Alborosie3 years ago
6 0
<span>c = speed of light = 3.00 x 10^5 km/s = 3.00 x 10^8 m/s
  λ = wavelength of the microwave radiation = 3.50 cm = 0.035 m
  f = frequency (in Hertz) = to be determined
    f = c/λ = 3.00 x 10^8 m/s / 0.035 m
  f = 8.57 x 10^9 Hz Frequency</span>
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At a certain temperature the vapor pressure of pure benzene is measured to be . Suppose a solution is prepared by mixing of benz
Marianna [84]

Answer:

P(C₆H₆) = 0.2961 atm

Explanation:

I found an exercise pretty similar to this, so i'm gonna use the data of this exercise to show you how to do it, and then, replace your data in the procedure so you can have an accurate result:

<em>"At a certain temperature the vapor pressure of pure benzene (C6H6) is measured to be 0.63 atm. Suppose a solution is prepared by mixing 79.2 g of benzene and 115. g of heptane (C7H16) Calculate the partial pressure of benzene vapor above this solution. Round your answer to 2 significant digits. Note for advanced students: you may assume the solution is ideal".</em>

<em />

Now, according to the data, we want partial pressure of benzene, so we need to use Raoul's law which is:

P = Xₐ * P°    (1)

Where:

P: Partial pressure

Xₐ: molar fraction

P°: Vapour pressure

We only have the vapour pressure of benzene in the mixture. We need to determine the molar fraction first. To do this, we need the moles of each compound in the mixture.

To get the moles:   n = m / MM

To get the molar mass of benzene (C₆H₆) and heptane (C₇H₁₆), we need the atomic weights of Carbon and hydrogen, which are 12 g/mol and 1 g/mol:

MM(C₆H₆) = (12*6) + (6*1) = 78 g/mol

MM(C₇H₁₆) = (7*12) + (16*1) = 100 g/mol

Let's determine the moles of each compound:

moles (C₆H₆) = 79.2 / 78 = 1.02 moles

moles (C₇H₁₆) = 115 / 100 = 1.15 moles

moles in solution = 1.02 + 1.15 = 2.17 moles

To get the molar fractions, we use the following expression:

Xₐ = moles(C₆H₆) / moles in solution

Xₐ = 1.02 / 2.17 = 0.47

Finally, the partial pressure is:

P(C₆H₆) = 0.47 * 0.63

<h2>P(C₆H₆) = 0.2961 atm</h2>

Hope this helps

7 0
2 years ago
Eading and
4vir4ik [10]

Answer: 25.8 g of Cl_2 will be produced from the decomposition of 73.4 g of AuCl_3

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} AuCl_3=\frac{73.4g}{303g/mol}=0.242moles

The balanced chemical reaction is:

2AuCl_3\rightarrow 2Au+3Cl_2  

According to stoichiometry :

2 moles of AuCl_3 produce =  3 moles of Cl_2

Thus 0.242 moles of  will produce= \frac{3}{2}\times 0.242=0.363mol of Cl_2

Mass of Cl_2= moles\times {\text {Molar mass}}=0.363mol\times 71g/mol=25.8g

Thus 25.8 g of Cl_2 will be produced from the decomposition of 73.4 g of AuCl_3

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borishaifa [10]

Answer:

Dynamic equilibrium occurs when the rate of the forward reaction equals the rate of the reverse reaction:

Explanation:

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The same ratio at equilibrium (when rate of forward reaction becomes equal to rate of backward reaction) is equilibrium constant.

when Q < Kc, a forward reaction is favored.

When when Q > Kc, a backward or reverse reaction is favored

So the first statement that

a) A reaction quotient (Q) larger than the equilibrium constant (K) means that the reaction will favor the production of more products: false

b) No the rate of forward and backward reaction are equal.

c) c. Dynamic equilibrium occurs when the rate of the forward reaction equals the rate of the reverse reaction: True

d) Dynamic equilibrium indicates that the amount of reactants and products are equal: This could be static equilibrium but not dynamic.

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Explanation:

Primary consumers eat producers (plants). Therefore, all the animals that eat the plants are primary consumers.

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