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3 years ago

7

Which characteristic distinguishes an estuary form other bodies of water

1 answer:

Readme [11.4K]3 years ago

3 0

An estuary is partly enclosed and forms a transition zone between rivers and oceans/ seas

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Mashutka [201]

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3 years ago

What is the name of the acid CH3COOH

romanna [79]

Answer:

CH3COOH is Acetic acid.

7 0

3 years ago

Question 4 to make a 0.500 m solution, one could take 0.500 moles of solute and add 1.00 l of solvent. enough solvent to make 1.

stealth61 [152]

The answer is enough solvent to make 1.00 L of solution. Since molarity is the number of moles of solute in one liter of solution, adding 0.500 mole solute to one liter solvent might not result to a solution with one liter total volume. Less than one liter solvent is first added to dissolve 0.500 mole solute and then the solution is carefully filled with more solvent until the solution reaches to one liter total volume. Hence, the resulting solution is a 0.500M concentration.

7 0

3 years ago

Read 2 more answers

If a sample contains 21.2 g N, how many moles of N does it contain?

cupoosta [38]

Hello!

If a sample contains 21.2 g N, how many moles of N does it contain?

0.66 mol

1.51 mol

14.01 mol

297.01 mol

We have the following data:

m (mass) = 21.2 g

MM (Molar mass of Nitrogen) = 14 g / mol

n (number of moles) = ?

Formula:

$n = \dfrac{m}{MM}$

Solving:

$n = \dfrac{m}{MM}$

$n = \dfrac{21.2\:\diagup\!\!\!\!\!g}{14\:\diagup\!\!\!\!\!g/mol}$

$\boxed{\boxed{n\approx 1.51\:mol}}\end{array}}\qquad\checkmark$

Answer:

1.51 mol

_______________________________

I Hope this helps, greetings ... Dexteright02! =)

5 0

4 years ago

Read 2 more answers

The accepted density of copper is 8.96 g/mL. Calculate the percent error of a student’s measurement which resulted in a density

uranmaximum [27]

Answer:

<h3>The answer is 1.12 %</h3>

Explanation:

The percentage error of a certain measurement can be found by using the formula

$P(\%) = \frac{error}{actual \: \: number} \times 100\% \\$

From the question

actual density = 8.96 g/mL

error = 8.96 - 8.86 = 0.1

We have

$p(\%) = \frac{0.1}{8.96} \times 100 \\ = 1.1160714...$

We have the final answer as

<h3>1.12 %</h3>

Hope this helps you

8 0

3 years ago