Answer:
390.85mL
Explanation:
Step 1:
Data obtained from the question.
Initial pressure (P1) = 780 torr
Initial volume (V1) = 400mL
Initial temperature (T1) = 40°C = 40°C + 273 = 313K
Final temperature (T2) = 25°C = 25°C + 273 = 298K
Final pressure (P2) = 1 atm = 760torr
Final volume (V2) =?
Step 2:
Determination of the final volume i.e the volume of the gas outside Matt's body.
The volume of the gas outside Matt's body can be obtained by using the general gas equation as shown below:
P1V1/T1 = P2V2/T2
780 x 400/313 = 760 x V2 /298
Cross multiply to express in linear form
313 x 760 x V2 = 780 x 400 x 298
Divide both side by 313 x 760
V2 = (780 x 400 x 298) /(313 x 760)
V2 = 390.85mL
Therefore, the volume of the gas outside Matt's body is 390.85mL
