Ask question

Ask question

All categories

3 years ago

10

What is the range of the function in this table?

2 answers:

marin [14]3 years ago

8 0

Hello from MrBillDoesMath!

Answer:

Choice B: {1,2,4}

Discussion:

The range of the function is the set of "y" values shown in the table, which is 1,4,4,2. As sets do not contain duplicate elements, the range is {1,2,4). This is Choice B

Thank you,

MrB

lyudmila [28]3 years ago

5 0

Answer:

Range ( 1, 2, 4).

Step-by-step explanation:

Given : Table of x and y.

To find : What is the range of the function in this table.

Solution : We have given table of x and y.

Range : range is the set of dependent values ( usually) of function on which the function is define.

Then , values of x are input values and values of y is depend on value of x.

So, Values of y are dependent values is the range.

Range ( 1, 2, 4).

Therefore, Range ( 1, 2, 4).

You might be interested in

The volume of a sphere whose diameter is 18 centimeters is

Ber [7]

Answer:

please give more clarification

5 0

3 years ago

What is the answer to 90 is 45% of what?

ANTONII [103]

..... 40.5 ...............

7 0

3 years ago

Read 2 more answers

Is 3 a factor of 73? ( Yes ) or ( No )

Mkey [24]

Answer:

The correct answer is no.

Step-by-step explanation:

If a number is a factor of another number, that means that it can be equally divided into it <em>evenly</em>.

I know that 3 x 20 = 60, and 73 - 60 = 13.

Since 3 is <em>not</em> a factor of 13, it is also <em>not</em> a factor of 73.

Hope this helps! :D

6 0

2 years ago

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

3 years ago

I need help on this 2 problems please help

Digiron [165]

Answer:

3. 294 m²

4. 185,856 mm²

Step-by-step explanation:

To find the surface area of any figure, you can simply find the sum of the areas of all the sides. In question 3, the figure is a triangular prism that has two triangular bases and three rectangular sides. The measurements for the triangles are b = 9m and h = 6m. The formula for the area of a triangle is base times height divided by 2, or 9 x 6 = 54/2 = 27 m². However, since there are two triangular bases, the area for both is 54 m². The measurements for the other three rectangles are given:

7(10) + 8(10) + 9(10) = 240 m² + 54 m² = 294 m²

The surface area of a cube is much easier since all sides are equal and can be found using the formula:

SA = 6s², where 's' represents the measure of a side.

SA = 6(176)² = 185,856 mm²

6 0

3 years ago