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Hatshy [7]
3 years ago
7

How do you solve y=3x+5

Mathematics
1 answer:
guajiro [1.7K]3 years ago
6 0
It depends how you want to solve it
you can plug it in on a calculator and It will show you how the equation looks on a graph( need graphing calculator).
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An item was bought for £3 000. It was sold for £1 800. What was the percentage loss? Please help
Gekata [30.6K]

Step-by-step explanation:

real real on the 11th July world population Day is celebrated on the table that day was across the world it is

6 0
3 years ago
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Please help !!
Maurinko [17]
Answer: The number of ceral boxes per day.

Because the slope will be [rise of the grah of the model function] / [run of the graph of the model function].

rise = [increase in the number of cereal boxes sold]

run = [days elapsed ]

rise / run = number of cereal boxes sold per day


8 0
3 years ago
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Help plz i will give brainliest to best answer!
katovenus [111]

Answer:

The answer is (4,14) because both lines pass through this point.

5 0
2 years ago
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How to express each of the following pairs of
vichka [17]

Answer:

<em>a) 3<x<8</em>

<em>b) -4<x<-2</em>

<em>c) -6<x<5</em>

<em>d) -21/4 < x-8/3</em>

<em>e) 0<x<7</em>

Step-by-step explanation:

Given the following inequalities

a)  x > 3, 2x - 3 < 15

Solve 2x - 3 < 15

2x < 15+3

2x<18

x<18/2

x<8

Combine x>3 and x<8

If x>3, then 3<x

On combining, we have:

3<x<8

b) For the inequalities 25 > 1 - 6x, 1 > 3x + 7

25 > 1 - 6x

25-1>-6x

24>-6x

Divide through by -6:

24/-6 > -6x/-6

-4 <x

For the inequality 1 > 3x + 7

1-7>3x

-6>3x

-6/3 > 3x/3

-2 > x

x < -2

Combining both results i.e -4 <x and x < -2, we will have:

-4<x<-2

c) For the inequalities 2x - 7<3< 27 + 4x

On splitting:

2x - 7<3 and 3< 27 + 4x

2x < 3+7

2x<10

x<5

Also for 3< 27 + 4x

3-27<4x

-24<4x

-24/4 < 4x/4

-6<x

Combining both solutions i.e x<5 and -6<x will give;

<em>-6<x<5</em>

d) For the inequalities 3x + 8 <0 < 21 + 4x

3x + 8 <0

3x < -8

x < -8/3

Also for 0 < 21 + 4x

0-21<4x

-21<4x

-21/4 < 4x/4

-21/4 < x

Combining -21/4 < x and x < -8/3 will give;

<em>-21/4 < x-8/3</em>

<em></em>

e) For the inequalities 5x - 36 < -1 < 2x – 1​

Split:

5x - 36 < -1

5x < -1+36

5x<35

5x/5 < 35/5

x < 7

For the expression -1 < 2x – 1​

-1+1 < 2x

0 < 2x

0<x

Combining both inequalities 0<x and x < 7 will give:

<em>0<x<7</em>

7 0
3 years ago
Anderson uses the discriminant to correctly find the number of real solutions of the quadratic equation one-halfx2 + 4x + 8 = 0.
amid [387]

Answer:

The discriminant of ax^2+bx+c is b^2-4ac.  

If the discriminant, d, is:

d<0, there are no real solutions (there are two imaginary solutions however)

d=0, there is one real solution

d>0, there are two real solutions

In this case d=16-32=-16 so there are two imaginary solutions.  Or from your answer choices, it can be said that there are no real number solutions becuse the discriminant is less than zero.

3 0
3 years ago
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