Answer:
There is a linear correlation between chest size and weight,0.8482
Step-by-step explanation:
Given that for a sample of eight bears, researchers measured the distances around the bears' chests and weighed the bears.
the value of the linear correlation coefficient is r = 0.921.
i.e. there is a strong positive correlation from the value of r.
(Two tailed test at 5% level for correlation coefficient)
Test statistic t =
p value <0.00001
Since p is less than 0.05 we reject H0
a) There is a linear correlation between chest size andweight
b)-- R^2 = 0.8482 proportion of the variation in weight can be explainedby the linear relationship between weight and chest size
Answer:
I dont but want to.
Hope this helps! :) ;-;
Step-by-step explanation:
X + 0.5y = 3
x^2 - y = 15
from the first equation:-
0.5y = 3 - x
y = 6 - 2x
Substitute for y in second equation:-
x^2 - (6 - 2x) = 15
x^2 + 2x - 21 = 0
x = [-2 +/- sqrt((4 - 4*-21)] / 2
= 3.6904 , -5.6904
Plugging in these into first equation we get
3.6904 + 0.5y = 3 so y = 2(3-3.6904) = -1.3808
-5.6904 + 0.5y = 3 so y = 2(3 + 5.6904) = 17.3808
Solution is x = 3.690, y = -1.381 ; x = -5.690, y = 17.38 ( to 4 s.f's)
820 + .06(820)
820 + 49.2
869.2
The cost of the car is $869.20.