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Mazyrski [523]
3 years ago
11

Write an equation for a line containing (-8,12) that is parallel to the line containing the points (3,2) and (-7,2)

Mathematics
2 answers:
jarptica [38.1K]3 years ago
6 0
First we need to find the slope.

slope = (y2 - y1) / (x2 - x1)

slope = (-5 - 2) / (5 - -3)

slope = (-7) / (5 + 3)

slope = -7/8

.

Point-slope form:

y - y1 = m(x - x1)

y - 2 = (-7/8)(x - -3)

y - 2 = (-7/8)(x + 3)

y - 2 = (-7/8)x - 21/8

y = (-7/8)x - 21/8 + 2

y = (-7/8)x - 21/8 + 16/8

y = (-7/8)x - 5/8

vfiekz [6]3 years ago
3 0
I don’t have a calculator but off the top of my head it’s -7/8
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(a) The system of the equations \left \{ {2x-3y\:=3} \atop {4x-6y\:=3}} \right. has no solution.

(b) The system of the equations \left \{ {4x-6y\:=10} \atop {16x-24y\:=40}} \right. has many solutions y=\frac{2x}{3}-\frac{5}{3}

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