Write an equation for a line containing (-8,12) that is parallel to the line containing the points (3,2) and (-7,2)

2 answers:

6 0

First we need to find the slope.

slope = (y2 - y1) / (x2 - x1)

slope = (-5 - 2) / (5 - -3)

slope = (-7) / (5 + 3)

slope = -7/8

.

Point-slope form:

y - y1 = m(x - x1)

y - 2 = (-7/8)(x - -3)

y - 2 = (-7/8)(x + 3)

y - 2 = (-7/8)x - 21/8

y = (-7/8)x - 21/8 + 2

y = (-7/8)x - 21/8 + 16/8

y = (-7/8)x - 5/8

vfiekz [6]3 years ago

3 0

I don’t have a calculator but off the top of my head it’s -7/8

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