Write an equation for a line containing (-8,12) that is parallel to the line containing the points (3,2) and (-7,2)
2 answers:
First we need to find the slope.
slope = (y2 - y1) / (x2 - x1)
slope = (-5 - 2) / (5 - -3)
slope = (-7) / (5 + 3)
slope = -7/8
.
Point-slope form:
y - y1 = m(x - x1)
y - 2 = (-7/8)(x - -3)
y - 2 = (-7/8)(x + 3)
y - 2 = (-7/8)x - 21/8
y = (-7/8)x - 21/8 + 2
y = (-7/8)x - 21/8 + 16/8
y = (-7/8)x - 5/8
I don’t have a calculator but off the top of my head it’s -7/8
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Answer:2
Step-by-step explanation:
I’m not exactly sure bc I’ve never heard a problem like that before but I believe that’s correct.
Answer:
x=2
Step-by-step explanation:
Isolate the variable by dividing each side by factors that don't contain the variable.
(-7/8)(-3/4)
multiply the numerators together
(-7)(-3)=21
multiply the denominators together
(-8)(-4)=32
answer:
21/32
