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4 years ago

Can you helpppp pleasse

Mathematics

1 answer:

ryzh [129]4 years ago

7 0

Answ 456

Step-by-step explanation:

ask your mom she might know unless she is to craycray

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OF bisects EOG. EOF = 5y + 10 and FOG = 6y + 3. Solve for y.

brilliants [131]

So the answer is : 5y + 10 = 6y + 3

  5y - 6y +10 = 3

-y= 3-10

-y= -7 Now you are looking for y not -y so you have to multiply or divide both side by (-1). It will be :

(-1) -y = (-1) -7
So:
Y = 7 Final answer.

7 0

3 years ago

Read 2 more answers

PLZ HELP

Rama09 [41]

Answer:

Step-by-step explanation:

1 2/3 in improper form is -> 5/3

4 1/6 in improper form is -> 25/6

5/3 is equal to-> 10/6

so.. 25 divided by 10 equals 2.5

so to fill the cylinder you'll need 3 sm cylinders (u can't only have a half of a cilinder)

7 0

3 years ago

Answer correctly for 5 star and brainliest

nataly862011 [7]

Answer:

$m=\frac{5}{2}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Step-by-step explanation:

Step 1: Define

Point (-2, -4)

Point (2, 6)

Step 2: Find slope m

Substitute [Slope Formula]: $m=\frac{6+4}{2+2}$
Evaluate Addition: $m=\frac{10}{4}$
Simplify: $m=\frac{5}{2}$

7 0

3 years ago

How many solutions does the system have? y=-5x-1 y=-5x+7

vesna_86 [32]

Answer:

Step-by-step explanation:

to do these types of problems, we must compare the slopes and the y int's

in y = mx + b form, the slope will be in the m position and the y int will be in the b position.

y = mx + b

y = -5x - 1......slope here is -5 and y int is -1

y = -5x + 7....slope here is -5 and y int is 7

learn these....it really helps

if the slopes are the same, but the y int different, there is no solution because ur lines are parallel

if the slopes are different and the y int are different, then there will be one solution

if the slopes are the same and the y int are the same, there is infinite solutions because u have the same line.

so the answer to this problem is : NO SOLUTIONS...ur lines are parallel and never cross

8 0

3 years ago

Differentiate Vx(x + 2) with respect to x.

Travka [436]

Answer:

$y'= \frac{3x+2}{2\sqrt{x} }$

General Formulas and Concepts:

Calculus

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Step-by-step explanation:

Step 1: Define

$y=\sqrt{x} (x+2)$

Step 2: Rewrite

$y=x^{\frac{1}{2} } (x+2)$

Step 3: Differentiate

Product Rule [Basic Power/Chain Rule]: $y'= \frac{1}{2} x^{\frac{1}{2} -1}(x+2)+x^{\frac{1}{2} }(1)$
Simplify: $y'= \frac{1}{2} x^{\frac{-1}{2}}(x+2)+x^{\frac{1}{2}}$
Rewrite: $y'= \frac{x+2}{2\sqrt{x} } + \sqrt{x}$
Add: $y'= \frac{3x+2}{2\sqrt{x} }$

7 0

3 years ago