Answer:
g=3
Step-by-step explanation:
f(g) = g^2 +3g
Let f(g) = 18
18 = g^2 +3g
Subtract 18 from each side
18-18 =g^2 +3g-18
0 = g^2 +3g-18
Factor
0 = (g+6) (g-3)
Using the zero product property
g+6 =0 g-3 =0
g = -6 g =3
The only solution listed is g=3
Answer:
-2/3
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The equation of the line is -6x - 2y = -18.
At the x-intercept, the value of y is zero.
Therefore
-6x - 2(0) = -18
-6x = -18
x = -18/(-6) = 3
Answer: 3.
These are all in vertex form,
y = a(x - p)² + q
When a is positive this makes a CUP (concave up positive) and has a minimum, not a maximum. When a is negative then the maximum is just when the squared term is 0, in which case
y = q
is the maximum.
From the figure g(x) has a maximum of 3 at x=2.
A. Positive coefficient, CUP, no max
B. CUP, no max
C. Negative coefficient, will have a max, at y=3, not greater than 3.
D. Negative coefficient, max at y=4
Answer: D
