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sergiy2304 [10]
3 years ago
15

What is the least common denominator of 1/2 and 3/7

Mathematics
2 answers:
MrMuchimi3 years ago
7 0

Answer:

The least common denominator is 14

Step-by-step explanation:

kompoz [17]3 years ago
6 0

Answer: 14

Step-by-step explanation:

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19

Step-by-step explanation:

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3 years ago
Read 2 more answers
Select the correct answer.
Rashid [163]

Answer: D. (4,3)

The x coordinates of A and B are 9 and -1 in that order. Add them up to get 9+(-1) = 9-1 = 8. Then divide by two to end up with 8/2 = 4. The midpoint has an x coordinate of 4.

Repeat for the y coordinates. Add them up: 8+(-2) = 8-2 = 6. Then divide by two: 6/2 = 3. The midpoint has an y coordinate of 3.

Those two coordinates pair up to get (x,y) = (4,3) which is the midpoint of segment AB.

7 0
3 years ago
Can someone do the work on this question so I can study what you did
Umnica [9.8K]
The answers and explanations are in the picture

8 0
3 years ago
A chemist has 200 mL of a 10% sucrose solution. She adds x mL of a 40% sucrose solution. The percent concentration, y, of the fi
user100 [1]

Answer:

The chemist needs to add 400mL of 40% solution.

Step-by-step explanation:

The equation

y=\frac{0.1(200)+0.4x}{200+x} *100

gives the percent concentration y of the final mixture, when x mL of the 40% solution are added.

Now we are asked, how many milliliters x of the 40% solution should the chemist add to get final percent concentration y=30; this is just a matter of solving the equation

30=\frac{0.1(200)+0.4x}{200+x} *100

and we solve it the following way:

30=\frac{0.1(200)+0.4x}{200+x} *100\\\\0.3 =\frac{0.1(200)+0.4x}{200+x}\\\\0.3(200+x)=0.1(200)+0.4x\\\\60+0.3x=20+0.4x\\\\40=0.1x\\\\x=\frac{40}{0.1} \\\\\boxed{x=400\:mL}

Thus, the chemist needs 400mL of 40% solution to get 30% concentration of the final mixture.

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4 years ago
Classify each expression by degree and by number of terms. Some answers may be used once and some way not be used at all so make
posledela

Answer:

899

Step-by-step explanation:

+

5 0
3 years ago
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