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3 years ago

Which of the following represents the y-intercept of the function y = log (x + 100) - 4 ? *

Mathematics

2 answers:

Llana [10]3 years ago

8 0

Answer:

its c bru

Step-by-step explanation:

LekaFEV [45]3 years ago

6 0

Answer:

Step-by-step explanation:

To find the y- intercept, let x = 0 in the equation and solve for y, that is

y = $log_{10}$ (0 + 100) - 4

= $log_{10}$ 100 - 4

= 2 - 4

= - 2 ← y- intercept → b

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Which of the following is not one of the 8th roots of unity?

Anika [276]

Answer:

1+i

Step-by-step explanation:

To find the 8th roots of unity, you have to find the trigonometric form of unity.

1. Since $z=1=1+0\cdot i,$ then

$Rez=1,\\ \\Im z=0$

and

$|z|=\sqrt{1^2+0^2}=1,\\ \\\\\cos\varphi =\dfrac{Rez}{|z|}=\dfrac{1}{1}=1,\\ \\\sin\varphi =\dfrac{Imz}{|z|}=\dfrac{0}{1}=0.$

This gives you $\varphi=0.$

Thus,

$z=1\cdot(\cos 0+i\sin 0).$

2. The 8th roots can be calculated using following formula:

$\sqrt[8]{z}=\{\sqrt[8]{|z|} (\cos\dfrac{\varphi+2\pi k}{8}+i\sin \dfrac{\varphi+2\pi k}{8}), k=0,\ 1,\dots,7\}.$

Now

at k=0, $z_0=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 0}{8}+i\sin \dfrac{0+2\pi \cdot 0}{8})=1\cdot (1+0\cdot i)=1;$

at k=1, $z_1=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 1}{8}+i\sin \dfrac{0+2\pi \cdot 1}{8})=1\cdot (\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=2, $z_2=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 2}{8}+i\sin \dfrac{0+2\pi \cdot 2}{8})=1\cdot (0+1\cdot i)=i;$

at k=3, $z_3=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 3}{8}+i\sin \dfrac{0+2\pi \cdot 3}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2};$

at k=4, $z_4=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 4}{8}+i\sin \dfrac{0+2\pi \cdot 4}{8})=1\cdot (-1+0\cdot i)=-1;$

at k=5, $z_5=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 5}{8}+i\sin \dfrac{0+2\pi \cdot 5}{8})=1\cdot (-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=-\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

at k=6, $z_6=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 6}{8}+i\sin \dfrac{0+2\pi \cdot 6}{8})=1\cdot (0-1\cdot i)=-i;$

at k=7, $z_7=\sqrt[8]{1} (\cos\dfrac{0+2\pi \cdot 7}{8}+i\sin \dfrac{0+2\pi \cdot 7}{8})=1\cdot (\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2})=\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2};$

The 8th roots are

$\{1,\ \dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ i, -\dfrac{\sqrt{2}}{2}+i\dfrac{\sqrt{2}}{2},\ -1, -\dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2},\ -i,\ \dfrac{\sqrt{2}}{2}-i\dfrac{\sqrt{2}}{2}\}.$

Option C is icncorrect.

5 0

2 years ago

2x - 6 y equals 24 negative 5 plus 6y equals negative 6

SCORPION-xisa [38]

I hope this helps you

8 0

3 years ago

What is the value of x? Enter your answer in the box. <br><br> x= ___cm

gogolik [260]

Answer:

x=5

Step-by-step explanation:

40/x=32/4

160=32x

160/32=32x/32

5=x

Hope this helps sweetie! ;)

3 0

3 years ago

A medical school admits 86 new applicants every year, let y represent the number of years and a represent the total of admitted

kkurt [141]

Answer:

a = 86y

Step-by-step explanation:

Given:

Number of applicants per year = 86

Find:

Equation represent total applicants

Computation:

Assume;

Total number of years = y

Total number of applicants = a

So,

Total number of applicants = Number of applicants per year x Total number of years

a = 86 x y

a = 86y

5 0

3 years ago

Is the length of the hypotenuse of a right triangle with legs that mea-

icang [17]

Answer:
Irrational Number

Step-by-step explanation:
So, since it's a right triangle, you can use Pythagorean Theorem to calculate the measure of the hypotenuse.

Pythagorean Theorem says the hypotenuse squared = the sum of the sides squared.

5² + 6² = 25 + 36 = 61

And the square root of 61 is 7.8102496.... and the decimal continues in no distinguishable pattern. Therefore, the length of the hypotenuse is an irrational number.

4 0

2 years ago