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4 years ago

10

The figure is made up of 2 cones and a cylinder. The

1 answer:

zhuklara [117]4 years ago

7 0

The area of cylinder is 3.82 cm^3. The area of the cone is 1.27 cm^3. Since there’s two cones, multiple that value by 2 and then add it to the volume of the cylinder. Your answer is approximately 6.36 cm^3

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10. For f(x) = 3 - 5x, find f(-5).<br> A. –22<br> B. -7<br> C. 3<br> D. 28

Artist 52 [7]

Answer:

D

Step-by-step explanation:

$3 - 5( - 5) \\ 3 - ( - 25) \\ 3 + 25 \\ 28$

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3 years ago

What percentage of the individuals rode the Ferris wheel and did not ride the roller coaster?

Ilia_Sergeevich [38]

Answer:

B and D

Step-by-step explanation:

they both make srnse to me

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3 years ago

which of the following equation as that of a line, a circle, an ellipse, a parabola, or a hyperbola is xy=4

Vitek1552 [10]

Try this option:
according to the equation it is a hyperbola.
The graph of this function is attached.

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3 years ago

Read 2 more answers

What is the value of A in the area model for finding the quotient of 4,340 ÷ 5?

Angelina_Jolie [31]

Value A:

5 x 800 = 4000

Answer is D) 4,000

8 0

3 years ago

The curves r1(t) = 2t, t2, t4 and r2(t) = sin t, sin 5t, 2t intersect at the origin. Find their angle of intersection, θ, correc

masya89 [10]

Answer:

Therefore the angle of intersection is $\theta =79.48^\circ$

Step-by-step explanation:

Angle at the intersection point of two carve is the angle of the tangents at that point.

Given,

$r_1(t)=(2t,t^2,t^4)$

and $r_2(t)=(sin t , sin5t, 2t)$

To find the tangent of a carve , we have to differentiate the carve.

$r'_1(t)=(2,2t,4t^3)$

The tangent at (0,0,0) is [ since the intersection point is (0,0,0)]

$r'_1(0)=(2,0,0)$ [ putting t= 0]

$|r'_1(0)|=\sqrt{2^2+0^2+0^2} =2$

Again,

$r'_2(t)=(cos t ,5 cos5t, 2)$

The tangent at (0,0,0) is

$r'_2(0)=(1 ,5, 2)$ [ putting t= 0]

$|r'_1(0)|=\sqrt{1^2+5^2+2^2} =\sqrt{30}$

If θ is angle between tangent, then

$cos \theta =\frac{r'_1(0).r'_2(0)}{|r'_1(0)|.|r'_2(0)|}$

$\Rightarrow cos \theta =\frac{(2,0,0).(1,5,2)}{2.\sqrt{30} }$

$\Rightarrow cos \theta =\frac{2}{2\sqrt{30} }$

$\Rightarrow cos \theta =\frac{1}{\sqrt{30} }$

$\Rightarrow \theta =cos^{-1}\frac{1}{\sqrt{30} }$

$\Rightarrow \theta =79.48^\circ$

Therefore the angle of intersection is $\theta =79.48^\circ$ .

8 0

3 years ago