The figure is made up of 2 cones and a cylinder. The

Mathematics

1 answer:

zhuklara [117]3 years ago

7 0

The area of cylinder is 3.82 cm^3. The area of the cone is 1.27 cm^3. Since there’s two cones, multiple that value by 2 and then add it to the volume of the cylinder. Your answer is approximately 6.36 cm^3

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Order 34 × 102, 1.2 × 107, 8.11 × 10–3 and 435 from least to greatest.

andrey2020 [161]

I will assume that this question is about scientific notation (also assuming that the first number is 3.4*10^2), where you can arrange the numbers by the exponent of the 10, so from least to greatest:
$8.11*10^{-3}$ , $3.4*10^{2}$ , 435, and $1.2*10^{7}$

6 0

3 years ago

Me please I don’t understand

irakobra [83]

9 + 4 = 13

She is 13 floors away

8 0

2 years ago

Read 2 more answers

Use the definition of a Taylor series to find the first three non zero terms of the Taylor series for the given function centere

Ket [755]

Answer:

$e^{4x}=e^4+4e^4(x-1)+8e^4(x-1)^2+...$

$\displaystyle e^{4x}=\sum^{\infty}_{n=0} \dfrac{4^ne^4}{n!}(x-1)^n$

Step-by-step explanation:

Taylor series expansions of f(x) at the point x = a

$\text{f}(x)=\text{f}(a)+\text{f}\:'(a)(x-a)+\dfrac{\text{f}\:''(a)}{2!}(x-a)^2+\dfrac{\text{f}\:'''(a)}{3!}(x-a)^3+...+\dfrac{\text{f}\:^{(r)}(a)}{r!}(x-a)^r+...$

This expansion is valid only if $\text{f}\:^{(n)}(a)$ exists and is finite for all $n \in \mathbb{N}$ , and for values of x for which the infinite series converges.

$\textsf{Let }\text{f}(x)=e^{4x} \textsf{ and }a=1$

$\text{f}(x)=\text{f}(1)+\text{f}\:'(1)(x-1)+\dfrac{\text{f}\:''(1)}{2!}(x-1)^2+...$

$\boxed{\begin{minipage}{5.5 cm}\underline{Differentiating $e^{f(x)}$}\\\\If $y=e^{f(x)}$, then $\dfrac{\text{d}y}{\text{d}x}=f\:'(x)e^{f(x)}$\\\end{minipage}}$