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Anit [1.1K]
3 years ago
7

Can Wendell make a triangular garden using pieces A, B, and F? Why or why not?

Mathematics
2 answers:
Likurg_2 [28]3 years ago
7 0
Yess he can chose B or F they are both good answers but I would tell you to pick F
Serhud [2]3 years ago
7 0

Answer:

Yes.  This can form an Acute Isosceles triangle with 2 equal sides and no angles over 90 degrees and the sum of two sides is larger than the third.

Step-by-step explanation:

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Answer:

Starting from the left.

4 × 3

5 × 5

2 × 5

4 × 5

4 × 4

1.5 × 2

Step-by-step explanation:

Divide all dimensions by 8.

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3 years ago
Tom took 10 notecards and arranged them in piles of How many piles did Tom make?
mezya [45]

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If there in piles of 2 you have 2 piles

Step-by-step explanation:

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3 years ago
Which situation can be represented by y = 20x?
stiv31 [10]

Answer:

A bakery makes y pies from 20 pounds of apples sold for x dollars.

Step-by-step explanation:

5 0
3 years ago
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According to the National Vital Statistics, full-term babies' birth weights are Normally distributed with a mean of 7.5 pounds a
Sav [38]

Answer:

68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 7.5, \sigma = 1.1

What is the probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

This is the pvalue of Z when X = 8.6 subtracted by the pvalue of Z when X = 6.4. So

X = 8.6

Z = \frac{X - \mu}{\sigma}

Z = \frac{8.6 - 7.5}{1.1}

Z = 1

Z = 1 has a pvalue of 0.8413

X = 6.4

Z = \frac{X - \mu}{\sigma}

Z = \frac{6.4 - 7.5}{1.1}

Z = -1

Z = -1 has a pvalue of 0.1587

0.8413 - 0.1587 = 0.6826

68.26% probability that a randomly selected full-term pregnancy baby's birth weight is between 6.4 and 8.6 pounds

6 0
3 years ago
An Item has a listed price of $30. If the sales tax rate is 5%, how much is the sales tax (in doll
DochEvi [55]

Answer:

sales tax is 1.5

Step-by-step explanation:

4 0
3 years ago
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