139 = x + (2x + 10)
139 = 3x + 10
129 = 3x
/3 /3
43 = x
Therefore
Answer:
75th term = 443
Step-by-step explanation:
Option C:
Area of the remaining paper = (3x – 4)(3x + 4) square centimeter
Solution:
Area of the square paper = sq. cm
Area of the square corner removed = 16 sq. cm
Let us find the area of the remaining paper.
Area of the remaining paper = Area of the square paper – Area of the corner
Area of the remaining =
=
Using algebraic formula:
Area of the remaining paper = (3x – 4)(3x + 4) square centimeter
Hence (3x – 4)(3x + 4) represents area of the remaining paper in square centimeters.
Answer:
D is the largest angle
Step-by-step explanation:
The angle opposite the largest side is the largest and the angle opposite the smallest side is the smallest.
Since 12 is the largest side, angle D is the largest
8 is the smallest side, F is the smallest angle
Answer:
The correct option is:
h = 1, k = 16
Step-by-step explanation:
y=4x^2-8x+20 =0
It is a quadratic formula in standard form:
ax^2+bx+c
where a = 4 , b = -8 and c=20
The vertex form is:
a(x − h)2 + k = 0
h is the axis of symmetry and (h,k) is the vertex.
Calculate h according to the following formula:
h = -b/2a
h= -(-8)/2(4)
h = 8/8
h = 1
Substitute k for y and insert the value of h for x in the standard form:
ax^2+bx+c
k = 4(1)^2+(-8)(1)+20
k = 4-8+20
k=-4+20
k = 16
Thus the correct option is h=1, k=16....