Y=mx+b
-b -b
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-by= mx
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m m
-by
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m
5?
Becouse a lot can be multiplyed by 1 and can be added to 4
Answer: G = 50°, I = 50°, H = 80°
Step-by-step explanation:
First and foremos, the sum of three angles of a triangle is 180°
2x + 2x + (4x - 20) = 180°
8x - 20 = 180°
8x = 180° + 20 (adding 20 on both sides)
8x = 200°
x = 200/8
x = 25
The value of the angles can be found by replacing the value of x with 25
2x = 2 x 25 = 50°
Therefore, the angle of two angles are 50°
And the other is (4 x 25) -20 = 80°
Answer:
Step-by-step explanation:
sin(θ+30∘)=cos50∘
⟹cos(90∘−(θ+30∘))=cos50∘
⟹cos(60∘−θ)=cos50∘
⟹cos(π3−θ)=cos5π18
Writing the general solution as follows
π3−θ=2nπ±5π18
⟹θ=π3−(2nπ±5π18)
Method 2: ,
sin(θ+30∘)=cos50∘
⟹sin(θ+30∘)=sin(90∘−50∘)
⟹sin(θ+30∘)=sin40∘
⟹sin(θ+π6)=sin2π9
Writing the general solution as follows
θ+π6=2nπ+2π9
⟹θ=2nπ+2π9−π6
⟹θ=2nπ+π18
or
θ+π6=(2n+1)π−2π9
⟹θ=2nπ+π−2π9−π6
⟹θ=2nπ+11π18
Hint 1: sin(a)=sin(b) iff a−b=2kπ or a+b=(2k+1)π for some k∈Z.
Hint 2: cos(40∘)=sin(50∘).
Hint:
sinθ=cos(90∘−θ)
cos50∘=sin40∘
can you solve for θ using the above?
0
Knowing the relation between sin(θ) and cos(θ) is quite crucial. One of the major relation is that the sine function and cosine function are fairly similar with 90∘ difference so,
Sin(x+90)=cos(x)
We are given x=50, so
x+90=30+θ
θ=110
or
180−140=40
This is θ+30 so,
θ=10∘
Answer:
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Step-by-step explanation: