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AleksandrR [38]
3 years ago
15

How many 1/16 inches are in one inch?

Mathematics
1 answer:
Dafna11 [192]3 years ago
8 0
The answer is 16 inches are in 1/16 inches
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Is angle ABC congruent to angle DCE
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I do not think I can answer this without any pictures.

Step-by-step explanation:

Sorry, but could you attach a link or maybe sketch it out?

4 0
4 years ago
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HELP PLEASE!!
MArishka [77]

The surface area of the box is 252in.2 so I guess you should go with 324

5 0
3 years ago
What is the surface area of a sphere with radius 4?
Verdich [7]

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SA =64 pi units ^2

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7 0
3 years ago
Si tenemos las siguientes funciones f(x) = 2x -1 y g(x) = 4x2 - 4x + 1 ¿Cuál seria el resultado de la multiplicación de f(x) * g
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Use math papa it’ll give you the answer
3 0
3 years ago
√secA+tanA/√secA-tanA × √cosecA-1/√cosecA+1=1
Snowcat [4.5K]

Use:\\\\\sec A=\dfrac{1}{\cos A}\\\\\tan A=\dfrac{\sin A}{\cos A}\\\\\csc A=\dfrac{1}{\sin A}\\\\\sqrt{ab}=\sqrt{a}\cdot\sqrt{b}\\\\\sqrt{\dfrac{a}{b}}=\dfrac{\sqrt{a}}{\sqrt{b}}\\---------------------------------\\\\\sec A+\tan A=\dfrac{1}{\cos A}+\dfrac{\sin A}{\cos A}=\dfrac{1+\sin A}{\cos A}\\\\\sec A-\tan A=\dfrac{1-\sin A}{\cos A}\\\\\csc A-1=\dfrac{1}{\sin A}-\dfrac{\sin A}{\sin A}=\dfrac{1-\sin A}{\sin A}\\\\\csc A+1=\dfrac{1+\sin A}{\sin A}


\dfrac{\sqrt{\sec A+\tan A}}{\sqrt{\sec A-\tan A}}\cdot\dfrac{\sqrt{\cos A-1}}{\sqrt{\cos A+1}}=1\\\\L_s=\sqrt{\dfrac{\sec A+\tan A}{\sec A-\tan A}\cdot\dfrac{\cos A-1}{\cos A+1}}=\sqrt{\dfrac{\frac{1+\sin A}{\cos A}}{\frac{1-\sin A}{\cos A}}\cdot\dfrac{\frac{1-\sin A}{\sin A}}{\frac{1+\sin A}{\sin A}}}\\\\=\sqrt{\dfrac{1+\sin A}{\cos A}\cdot\dfrac{\cos A}{1-\sin A}\cdot\dfrac{1-\sin A}{\sin A}\cdot\dfrac{\sin A}{1+\sin A}}\\\\\text{Everything are simplified}\\\\=\sqrt{1}=1=R_s

7 0
3 years ago
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