Answer:
225.78 grams
Step-by-step explanation:
To solve this question, we would be using the formula
P(t) = Po × 2^t/n
Where P(t) = Remaining amount after r hours
Po = Initial amount
t = Time
In the question,
Where P(t) = Remaining amount after r hours = unknown
Po = Initial amount = 537
t = Time = 10 days
P(t) = 537 × 2^(10/)
P(t) = 225.78 grams
Therefore, the amount of iodine-131 left after 10 days = 225.78 grams
66 is the anwer I think I'm not for sure I hope this helps and you get it right
This equation can have a number of solutions. Typically when solving a two-variable equation, you are looking for the slope intercept form of the line. In this case that is:
y = 3x - 1
Answer: (-x, y-7)
<u>Step-by-step explanation:</u>
A reflection across the y-axis changes the sign of the x-value.
(x, y) → (-x, y)
Shifting down 7 units subtracts 7 from the y-value.
(-x, y) → (-x, y-7)
