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DIA [1.3K]
3 years ago
13

Find the perimeter ​

Mathematics
1 answer:
Inga [223]3 years ago
6 0

Answer:

56

Step-by-step explanation:

Perimeter= 4S

Perimeter= 4(5)

Perimeter= 20

Perimeter 2= 2(L+W)

Perimeter 2= 2(11+7)

Perimeter 2= 22+14

Perimeter 2= 36

Total Perimeter= P1+P2

Total Perimeter= 20+36

Total Perimeter= 56

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G(-4, -8) and H(-15, -3). What is the slope of GH?
Masteriza [31]

Answer:

G(x1,y1)= (-4,-8)

H(x2,y2)=(-15,-3)

Slope = (y2-y1)/(x2-x1)

=(-3-(-8))/ (-15-(-4))

= (-3+8)/(-15+4)

=5/-11

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3 years ago
Maria created a graph of B(t), the temperature over time. For the interval between t = 3 and t = 7, the average rate of change i
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Answer:

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Step-by-step explanation:

cause i big brain

4 0
3 years ago
WILL MARK BRAINLEIST
lina2011 [118]

Answer:

decrease by 50%

Step-by-step explanation:

\frac{0.4x}{0.8y} =\frac{x}{2y}      

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6 0
3 years ago
A cement walkway of uniform width has been built around an in-ground rectangular pool. the area of the walkway is 1344 square fe
Elza [17]

Answer:

6 feet.

Step-by-step explanation:

Dimensions of the Pool =80 feet long by 20 feet wide

Area of the walkway =1344 square feet.

If the width of the walkway=w

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  • Width of the Larger Rectangle =20+2w

Area of the Walkway =Area of the Larger Rectangle - Area of the Pool

1344=(80+2w)(20+2w)-(80*20)\\1344=80*20+160w+40w+4w^2-80*20\\4w^2+200w=1344\\4w^2+200w-1344=0\\We factorize\\4(w^2+50w-336)=0\\4(w^2-6w+56w-336)=0\\w(w-6)+56(w-6)=0\\(w-6)(w+56)=0\\w-6=0$ or $ w+56=0\\w=6$ ft or $ w=-56$ \\Therefore, the width of the walkway , w=6 feet.

6 0
3 years ago
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