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3 years ago

If y=12 when x=6 determine y when x=18

1 answer:

5 0

Y will equal 36. You can figure this out because you know y is double the value of x. If x is 18,you can just multiply it by 2, which equals 36

You might be interested in

Round this “0.7660444431”into 4 decimals places!!!!!

ANTONII [103]

Answer:

.7660

Step-by-step explanation:

when you get to 0 at 7660 you round with the number next to it if its 5 or bigger you add a one to the number since 4 isn't greater than or equal to 5 than your numbers stay the same

5 0

2 years ago

Solve the problem. The systolic blood pressures of the patients at a hospital are normally distributed with a mean of 136mm Hg a

shtirl [24]

<span> we know that the 90 percentile in Z-score is ≈ 1.28 then,
=136 ± 1.28(13.8)
=(118.336 , 153.664)
</span>hope it helps

6 0

2 years ago

If you answer this i will give you the BRAINLIEST Pls answer Asap

Eva8 [605]

Answer:

You know that negative 3 1/2 is the lowest number so you would put that first. The greatest number would be the coldest in Celsius, and 1/20 would be the last question (the sea level) if calculations are correct, you would get full credit.

5 0

2 years ago

According to a recent survey, the population distribution of number of years of education for self-employed individuals in a c

creativ13 [48]

Answer:

a) X: number of years of education

b) Sample mean = 13.5, Sample standard deviation = 0.4

c) Sample mean = 13.5, Sample standard deviation = 0.2

d) Decrease the sample standard deviation

Step-by-step explanation:

We are given the following in the question:

Mean, μ = 13.5 years

Standard deviation,σ = 2.8 years

a) random variable X

X: number of years of education

Central limit theorem:

If large random samples are drawn from population with mean $\mu$ and standard deviation $\sigma$ , then the distribution of sample mean will be normally distributed with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$

b) mean and the standard for a random sample of size 49

$\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{49}} = 0.4$

c) mean and the standard for a random sample of size 196

$\mu_{\bar{x}} = \mu = 13.5\\\\\sigma_{\bar{x}} = \dfrac{\sigma}{\sqrt{n}} = \dfrac{2.8}{\sqrt{196}} = 0.2$

d) Effect of increasing n

As the sample size increases, the standard error that is the sample standard deviation decreases. Thus, quadrupling sample size will half the standard deviation.

7 0

3 years ago

The area of a triangle is 1/2*(base)*(height) or base times height divided by two.

blagie [28]

Answer:

both

Step-by-step explanation:

7 0

2 years ago