<span>Answer:
Roma Sherry drove 330 miles from her hometown to Tucson. During her return trip, she was able to increase her speed by 11 mph. If her return trip took 1 hour less time, find her original speed and her speed returning home.
:
Let s = original speed
then
(s+11) = return speed
:
Write a time equation: Time = distance%2Fspeed
:
Original time = return time + 1 hr
330%2Fs = 330%2F%28%28s%2B11%29%29 + 1
:
Multiply equation by s(s+11) and you have:
330(s+11) = 330s + s(s+11)
:
330s + 3630 = 330s + s^2 + 11s
:
0 = 330s - 330s + s^2 + 11s - 3630
:
A quadratic equation:
s^2 + 11s - 3630 = 0
Factor this to:
(s + 66)(s - 55) = 0
Positive solution
s = 55 mph is original speed.
:
Find the time
330/55 = 6 hr, original time
and
330/66 = 5 hrs, faster time; confirms our solution.</span>
Answer:
Kevin is going to be able to have enough money for the concert the fastest
Philip needs at least 4 weeks
Kevin needs at least 3 weeks
Step-by-step explanation:
<u>Philip</u>
- $8.75/hour * 6 hours/weekend * 1 weekend/week = $52.5/week
Let's call x to the number of weeks Philip needs to reach $225.
52.5*x + 45 = 225
52.5*x = 225 - 45
x = 180/52.5
x = 3.43
He needs at least 4 weeks
<u>Kevin</u>
- 3 hours/day * $7.5/hour *3 days/week = $67.5/week
Let's call y to the number of weeks Kevin needs to reach $225.
67.5*y + 30 = 225
67.5*y = 225 - 30
y = 195/67.5
y = 2.9
He needs at least 3 weeks
Answer:
A
Step-by-step explanation:
(y-5) / (7-5) = (x-1) / (2-1)
(y-5) / 2 = x-1
y-5 = 2x -2
y = 2x +3
Answer:
Step-by-step explanation:
y = 3x - 5.....input values are x and output values are y
so if ur input (x) is 2.....sub 2 in for x and find ur output (y)
y = 3x - 5
y = 3(2) - 5
y = 6 - 5
y = 1 <=== ur output value
3y - 1 < 3
Isolate the y. Treat the less than or equal like an equal sign.
Do the opposite of PEMDAS. First, add 1 to both sides
3y - 1 (+1) < 3 (+1)
3y < 4
Next, divide 3 from both sides
3y/3 < 4/3
y < 4/3
y < 4/3 is your answer
hope this helps
