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4 years ago

7

Writing Exponential Functions from Scenarios A patient is given a 50 mg dose of medicine. The medicine's effectiveness decreases

every hour at a constant rate of 40%. What is the exponential decay function that models this scenario? How much medicine will be left in the patient's system after 2 hours?
A. f(x) = 50(0.40)x; 8 mg
B. f(x) = 50(0.60)x; 18 mg
C. f(x) = 50(40)x; 80,000 mg
D. f(x) = 50(60)x; 180,000 mg

2 answers:

Mariana [72]4 years ago

5 0

Answer:

The answer is B - f(x) = 50(0.60)x; 18 mg

Step-by-step explanation:

allochka39001 [22]4 years ago

4 0

Wouldn't your answer be A because it is 40% which is 0.4 as a decimal?

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an initial investment of $480 earns interezt for 7 years in an account that earns 13% interest, compounded quarterly. Find the a

Travka [436]

Answer:

$1,175.34

Step-by-step explanation:

To solve for the total amount after 7 years. We need to use the formula:

$A = P(1+\dfrac{r}{n})^{nt}$

Let's first break down all the variables that we have.

P = 480

r = 13% or 0.13

n = 4 (Quarterly)

t = 7 years

Now we simply substitute the values into the formula.

$A = P(1+\dfrac{r}{n})^{nt}$

$A = 480(1+\dfrac{0.13}{4})^{4(7)}$

$A = 480(1+\dfrac{0.13}{4})^{28}$

$A = 480(1+0.0325)^{28}$

$A = 480(1.0325)^{28}$

$A = 480(2.45)$

$A = $1,175.34$

The account will have $1,175.34 after the 7 year period.

7 0

3 years ago

A person is standing on a cliff that is 200ft above a body of water. The person looks down at an angle of depression of 42o at a

velikii [3]

Answer:

524.5 feet

Step-by-step explanation:

Given: Height of cliff= 200 ft

Angle of depression at sail boat is 42°

Angle of depression at yacht is 15°

Lets assume distance sailboat from the bottom of cliff is " $d_1$ "

And assume distance yacht from the bottom of cliff is " $d_2$ "

Now using tangent rule to solve it.

we know, $tan\theta = \frac{opposite}{adjacent}$

Distance sailboat from the bottom of cliff; $tan 42= \frac{200}{d_1}$

Using trignometry table to know the value of tan 42°

⇒ $0.90= \frac{200}{d_1}$

cross multiplying both side.

⇒ $d_1= \frac{200}{0.90} = 222.22 \approx 222$

∴ Distance sailboat from the bottom of cliff ( $d_1)$ = 222 feet

Distance yatch from the bottom of cliff; $tan 15= \frac{200}{d_2}$

Using trignometry table to know the value of tan 15°

⇒ $0.2679= \frac{200}{d_2}$

cross multiplying both side.

⇒ $d_2= \frac{200}{0.2679} = 746.54 \approx 746.5$

∴Distance yacht from the bottom of cliff $(d_2)$ = 746.5 feet.

Next, finding the distance between sailboat and yacht.

Distance between sailboat and yacht = $d_2-d_1$

⇒ Distance between sailboat and yacht= $746.5-222= 524.5\ ft$

∴ Distance between sailboat and yacht is 524.5 feet.

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3 years ago

Please answer show all your work or tell me the steps

sukhopar [10]

Answer:

for question 1 the answer is

Step-by-step explanation:

1)it would be 78.08-64 = 14 soo the precent is 14

7 0

3 years ago

Read 2 more answers

8(1 - 5x) + 5 = -2 + 5x

andriy [413]

X=1/3
Distribute 8 through the parentheses
8-40x+5=-2+5x
Add the numbers
13-40x+5=-2+5x

Answer: x=1/3

7 0

3 years ago

you invested $1000 and at the end of one year you had $1090. What was the annual intetest on the investment? Presume simple inte

Brilliant_brown [7]

The interest rate will be found as follows:
I=(PRT)
I=1090-1000=$90
thus plugging in the value we get:
90=(1000*R*1)
90=1000R
thus
R=90/1000
R=0.09~9%

3 0

3 years ago