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bonufazy [111]
4 years ago
7

x2 + y2 − 4x + 12y − 20 = 0 (x − 6)2 + (y − 4)2 = 56 x2 + y2 + 6x − 8y − 10 = 0 (x − 2)2 + (y + 6)2 = 60 3x2 + 3y2 + 12x + 18y −

15 = 0 (x + 2)2 + (y + 3)2 = 18 5x2 + 5y2 − 10x + 20y − 30 = 0 (x + 1)2 + (y − 6)2 = 46 2x2 + 2y2 − 24x − 16y − 8 = 0 x2 + y2 + 2x − 12y − 9 = 0 Pairs arrowBoth arrowBoth arrowBoth arrowBoth
Mathematics
1 answer:
snow_tiger [21]4 years ago
7 0
For this case, what we must do is fill squares in all the expressions until we find the correct result.
 We have then:
 
 x2 + y2 − 4x + 12y − 20 = 0 x2 + y2  − 4x + 12y = 20
 x2  − 4x + y2 + 12y = 20
 x2  − 4x + (12/2)^2 + y2 + 12y  + (-4/2)^2 = 20 + (12/2)^2 + (-4/2)^2
 x2  − 4x + (6)^2 + y2 + 12y  + (-2)^2 = 20 + (6)^2 + (-2)^2
 x2  − 4x + 36 + y2 + 12y  + 4 = 20 + 36 + 4
 (x − 2)2 + (y + 6)2 = 60 

 
3x2 + 3y2 + 12x + 18y − 15 = 0 
 
x2 + y2 + 4x + 6y − 5 = 0 
 x2 + y2 + 4x + 6y  = 5 
 x2  + 4x + (4/2)^2 + y2 + 6y + (6/2)^2 = 5 + (4/2)^2 + (6/2)^2 
 x2  + 4x + (2)^2 + y2 + 6y + (3)^2 = 5 + (2)^2 + (3)^2 
 x2  + 4x + 4 + y2 + 6y + 9 = 5 + 4 + 9 
 (x + 2)2 + (y + 3)2 = 18 

 2x2 + 2y2 − 24x − 16y − 8 = 0
 x2 + y2 − 12x − 8y − 4 = 0
 x2 + y2 − 12x − 8y = 4 
 x2 − 12x + (-12/2)^2 + y2 − 8y + (-8/2)^2 = 4 + (-12/2)^2 + (-8/2)^2
 x2 − 12x + (-6)^2 + y2 − 8y + (-4)^2 = 4 + (-6)^2 + (-4)^2
 x2 − 12x + 36 + y2 − 8y + 16 = 4 + 36 + 16
 (x − 6)2 + (y − 4)2 = 56 

 x2 + y2 + 2x − 12y − 9 = 0
 x2 + y2  + 2x - 12y = 9
 x2  + 2x + y2 - 12y = 9
 x2  + 2x + (2/2)^2 + y2 - 12y  + (-12/2)^2 = 9 + (2/2)^2 + (-12/2)^2
 x2  + 2x + (1)^2 + y2 - 12y  + (-6)^2 = 9 + (1)^2 + (-6)^2
 x2  + 2x + 1 + y2 - 12y  + 36 = 9 + 1 + 36
 (x + 1)2 + (y − 6)2 = 46
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The value of f(0) is -1

<h3>What is a function?</h3>

A function can be defined as an expression, law or rule that explains the relationship between two variables; a dependent and an independent variable.

Given the function;

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f(0) = -(0) - 1

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HELP ASAP<br> Find the 15th term or the geometric sequence 7, -21, 63,
mihalych1998 [28]
<h3><u>Answer:</u></h3>

33480783

<h2><u>Step-by-step explanation:</u></h2>

<u>Finding the Common Ratio:</u>

We know that the formula for the common ratio of a GP is:

r = aₙ / (aₙ₋₁)        <em>(Where n is any integer)</em>

<em>replacing the values, taking n=2</em>

r = -21 / 7

r = -3

<u>Solving for the 15th Term:</u>

We know that the Formula for the nth term of a GP:

G(n) = a * r ⁿ⁻¹     <em>(where a is the first term and r is the common ratio)</em>

<em>replacing the values (taking n = 15 since we need the 15th term)</em>

G(15) = 7 * (-3)¹⁴

G(15) = 33480783

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5 0
3 years ago
The coldest temperature recorded in Alaska was –80°F. This was 10°F warmer than the coldest temperature recorded in Siberia. Whi
Klio2033 [76]

The equation that can be used to find the coldest temperature recorded in Siberia is y + 10  =  -80

Let the coldest temperature in Alaska be x

The coldest temperature recorded in Alaska was –80°F

x  =  –80°F

Let the coldest temperature in Siberia be y

The coldest temperature recorded in Alaska was 10°F warmer than the coldest temperature recorded in Siberia

This can be interpreted as:

Coldest temperature in Alaska  =  Coldest temperature in Siberia  +  10

x    =  y   +   10................(*)

Since x = -80

Substitute x = -80 into equation (*)

-80   =   y    +   10

This can be re-written as:

y  +  10   =   -80

The equation that can be used to find the coldest temperature recorded in Siberia is y + 10  =  -80

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7 0
2 years ago
Sebastian wants to create a right triangle with side lengths 14 inches, 48 inches, and 5
allochka39001 [22]

Answer: Choice A

\text{Yes, because } 14^2+48^2 \text{ is equal to } 50^2

=======================================================

Explanation:

The pythagorean theorem is a^2+b^2 = c^2

The value of c is always the longest side, aka hypotenuse.

The order of 'a' and b doesn't matter.

So a = 14, b = 48, c = 50

We have a^2+b^2 = 14^2+48^2 = 196+2304 = 2500

We also have c^2 = 50^2 = 2500

Both sides result in 2500 which proves that 14^2+48^2 = 50^2 is a true statement. Therefore, we do have a right triangle.

7 0
2 years ago
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