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Alexandra [31]
3 years ago
8

The sum of Louise's age and Todd's age is 34 years. Five years ago, the sum of twice Louise's age and three times Todd's age was

61 years. How old are they now?
Mathematics
1 answer:
Luda [366]3 years ago
8 0
L+T=34 \ => \boxed{L=34-T}\\\\ 2(L-5)+3(T-5)=61 \\\\ 2(34-T-5)+3T-15=61 \\\\ 68-2T-10+3T-15=61 \\\\ T+43=61 \\\\ T=61-43 \\\\ \boxed{T=18 \ years \ has \ Todd} \\\\ L=34-18 \\\\ \boxed{L=16 \ years \ has \ Louis}
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Suppose that f(t) is continuous and twice-differentiable for t≥0. Further suppose f″(t)≥9 for all t≥0 and f(0)=f′(0)=0. Using th
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Give me a heart and I'll tell you the answer
5 0
3 years ago
Fatima paid for 5 pallets of grass to be delivered each pallet cost $129.95. Fatima paid $76.20 for delivery. What is the total
lianna [129]

Answer:

$725.95

Step-by-step explanation:

First, calculate how much she paid for the 5 pallets

Each pallet costs 129.95, and she paid for 5, so we can multiply the 2 numbers

129.95*5=649.75

Then, add the delivery cost

649.75+76.20=725.95

So the total amount she paid is $725.95

Hope this helps! :)

3 0
3 years ago
1 /3 − (−1 /5 ) <br><br> a. -1/2<br> b. 1/4<br> c. 2/15<br> d. 8/15
Alexandra [31]

Answer:

D. 8/15

Step-by-step explanation:


8 0
3 years ago
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Consider a paint-drying situation in which drying time for a test specimen is normally distributed with σ = 7. The hypotheses H0
pshichka [43]

Answer:

(a) The value \bar x = 72.3 is 1.21 standard deviations below the null value of <em>μ</em>.

(b) The mean drying time of paint is not less than 74.

Step-by-step explanation:

The hypothesis for the single mean test is:

<em>H₀</em>: <em>μ</em> = 74 vs. <em>Hₐ</em>: μ < 74.

The information provided is:

<em>σ</em> = 7

<em>n</em> = 25

As the population standard deviation is known, we will use a <em>z</em>-test for single mean.

(a)

The <em>z</em>-score is a Normal distribution with mean 0 and variance 1. It is also defined as the number of standard deviations a raw score is from the mean.

The <em>z</em>-score for sample mean is given by:

z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}

If \bar x = 72.3 compute the corresponding <em>z</em>-score as follows:

z=\frac{\bar x-\mu}{\sigma/\sqrt{n}}

  =\frac{72.3-74}{7/\sqrt{25}}\\=-1.21

Thus, the value \bar x = 72.3 is 1.21 standard deviations below the null value of <em>μ</em>.

(b)

So the test statistic is, <em>z</em> = -1.21.

Compute the <em>p</em>-value of the test as follows:

p-value=P(Z

*Use a <em>z</em>-table.

The decision rule says to, reject the null hypothesis if the <em>p</em>-value is less than the significance level <em>α</em> = 0.01 and vice-versa.

<em>p</em>-value = 0.1131 < <em>α</em> = 0.01

The null hypothesis was failed to be rejected.

Thus, the mean drying time of paint is not less than 74.

6 0
2 years ago
PLease help with this question? I also need an explanation on how you got the answer
Tema [17]

Answer:

hmmmmmm

Step-by-step explanation:2

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3 years ago
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