Question

The sum of Louise's age and Todd's age is 34 years. Five years ago, the sum of twice Louise's age and three times Todd's age was 61 years. How old are they now?

Answer 1

$L+T=34 \ => \boxed{L=34-T}\\\\ 2(L-5)+3(T-5)=61 \\\\ 2(34-T-5)+3T-15=61 \\\\ 68-2T-10+3T-15=61 \\\\ T+43=61 \\\\ T=61-43 \\\\ \boxed{T=18 \ years \ has \ Todd} \\\\ L=34-18 \\\\ \boxed{L=16 \ years \ has \ Louis}$