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Alexandra [31]
3 years ago
8

The sum of Louise's age and Todd's age is 34 years. Five years ago, the sum of twice Louise's age and three times Todd's age was

61 years. How old are they now?
Mathematics
1 answer:
Luda [366]3 years ago
8 0
L+T=34 \ => \boxed{L=34-T}\\\\ 2(L-5)+3(T-5)=61 \\\\ 2(34-T-5)+3T-15=61 \\\\ 68-2T-10+3T-15=61 \\\\ T+43=61 \\\\ T=61-43 \\\\ \boxed{T=18 \ years \ has \ Todd} \\\\ L=34-18 \\\\ \boxed{L=16 \ years \ has \ Louis}
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In a two digit number, t = the tens digit and u = the ones digit. Which of the expressions below shows the value of its reversal
Leni [432]

10u + t is the expressions shows the value of the reversal of digits in a two digit number, t = the tens digit and u = the ones digit. This can be obtained by multiplying 10 with the tens digit and adding unit digit.

<h3>Which is the required expressions?</h3>

Given that, in a two digit number,

t = the tens digit

u = the ones digit

The expression for the digit will be ,

10×t + u = 10t + u

The value of its reversal,

u = the tens digit

t = the ones digit

10×u + t = 10u + t is the required expression

For example,

37 = 10×3 + 7 = 30 + 7 and its reverse 73 = 10×7 + 3 = 70 + 3

Hence 10u + t is the expressions shows the value of the reversal of digits in a two digit number, t = the tens digit and u = the ones digit.

Learn more about algebraic expressions here:

brainly.com/question/19245500

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4 0
1 year ago
I Really Need Help With This Please.
Flura [38]
ABC=DBC

(This will probably be a way more complex explanation than you need but it’s what I did.)

Okay so you know B=B because they’re both right angles. You know A=D because of the isosceles triangle theorem- if two sides of a triangle are congruent, then the angles opposite those sides are congruent. That leaves C=C. If B=B and A=D and all triangles add up to 180 degrees, C and C need to be the same.
6 0
3 years ago
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What is 1/5 divided by 1/2
Len [333]
The answer to your question is 0.1
4 0
3 years ago
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P³ = 1/8 please help me if anybody can .
ivanzaharov [21]

Answer:

p= \dfrac{1}{2}

Step-by-step explanation:

Given equation:

p^3=\dfrac{1}{8}

Cube root both sides:

\implies \sqrt[3]{p^3}= \sqrt[3]{\dfrac{1}{8}}

\implies p= \sqrt[3]{\dfrac{1}{8}}

\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:

\implies p= \left(\dfrac{1}{8}\right)^{\frac{1}{3}}

\textsf{Apply exponent rule} \quad \left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}:

\implies p= \dfrac{1^{\frac{1}{3}}}{8^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad 1^a=1:

\implies p= \dfrac{1}{8^{\frac{1}{3}}}

Rewrite 8 as 2³:

\implies p= \dfrac{1}{(2^3)^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:

\implies p= \dfrac{1}{2^{(3 \cdot \frac{1}{3})}}

Simplify:

\implies p= \dfrac{1}{2^{\frac{3}{3}}}

\implies p= \dfrac{1}{2^{1}}

\implies p= \dfrac{1}{2}

3 0
1 year ago
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The first term of a geometric sequence is 3 and the multiplier, or ratio, is 2. what is the sum of the first 6 terms of the sequ
storchak [24]
Answer:

288

Explanation:

As first term in sequence is 3 so multiplying it by common ratio 5 we get 15, then multiplying 15 by 5 we get 45 and so on the sequence is
<span>3,15,45,225</span>
whose sum is 288

5 0
3 years ago
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