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Alexandra [31]
3 years ago
8

The sum of Louise's age and Todd's age is 34 years. Five years ago, the sum of twice Louise's age and three times Todd's age was

61 years. How old are they now?
Mathematics
1 answer:
Luda [366]3 years ago
8 0
L+T=34 \ => \boxed{L=34-T}\\\\ 2(L-5)+3(T-5)=61 \\\\ 2(34-T-5)+3T-15=61 \\\\ 68-2T-10+3T-15=61 \\\\ T+43=61 \\\\ T=61-43 \\\\ \boxed{T=18 \ years \ has \ Todd} \\\\ L=34-18 \\\\ \boxed{L=16 \ years \ has \ Louis}
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We are aware that any straight line's equation can be expressed as

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where m denotes the slope and c denotes a constant.

Also, two perpendicular lines' slopes are the negative reciprocals of one another.

Here, the equation of the given straight line is

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i.e. 8y = 4 -3x

i.e. y = (4/8) - (3/8)x

Now the negative reciprocal of - 3/8 is 8/3.

Then we can write the equation of the perpendicular line is

y = (8/3)x + c ...(1)

Since (1) passes through the point (8, -9), so we can put x = 8 and y = -9 in (1) to get the value of c.

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Learn more about perpendicular lines here -

brainly.com/question/12209021

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