Answer:
Time t = 2 seconds
It will reach the maximum height after 2 seconds
Completed question;
Amir stands on a balcony and throws a ball to his dog who is at ground level. The ball's height, in meters above the ground, after t seconds that Amir has thrown the ball is given by:
H (t) = -(t-2)^2+9
many seconds after being thrown will the ball reach its maximum height?
Step-by-step explanation:
The equation of the height!
h(t) = -(t-2)^2 + 9 = -(t^2 -4t +4) + 9
h(t) = -t^2 +4t -4+9
h(t) = -t^2 + 4t +5
The maximum height is at dh/dt = 0
dh/dt = -2t +4 = 0
2t = 4
t = 4/2 = 2
Time t = 2 seconds
It will reach the maximum height after 2 seconds
Answer: 829.44 ft²
Step-by-step explanation:
Correction - The walkway is 31.2 feet wide.
To solve this, first find the area of the fountain:
Area of a square = Length * Width
= 12 * 12
= 144 ft²
The find the area of the walkway including the fountain:
= 31.2 * 31.2
= 973.44 ft²
To find the area of the walkway alone, subtract the area of the square from the area of the rectangle:
= 973.44 - 144
= 829.44 ft²
Answer:
y = x - 1
Step-by-step explanation:
Find the slope:
(-4 - (-2))/(-3 - (-1))
-2/-2 = 1
y = x + b
Plug in one of the points:
(-1,-2)
-2 = -1 + b
b = -1
y = x - 1
Answer:
9÷x is the correct answer
Answer:
-29m+62n
Step-by-step explanation:
5 (3m+6n)-4 (11m-8m)
15m+30n-44m+30n
15m-44m +32n+30n
-29m +62n
