Hey there!
In order to solve for the percentage of water in the compound, you will first need to find its total molar mass. You can do this by adding up the molar masses of each individual element in the compound. Then, you will divide the mass that you find of the water molecules by the total mass to get the percentage.
→ Na₂CO₃ ×<span> 10 H</span>₂<span>O
</span>→ Na₂ = 22.9898 × 2 = 45.9796
→ C = 12.0107
→ O₃ = 15.999 × 3 = 47.997
→ 10 H₂O = 18.015 × 10 = 180.15
Now, just add all of those numbers up for the total molar mass.
→ 45.9796 + 12.0107 + 47.997 + 180.15 = <span>286.1373
</span>
The last step is to divide the molar mass of the 10 water molecules by the total mass.
→ 180.15 ÷ 286.1373 = <span>0.62959 </span>≈ 0.63
Your answer will be about 63%.
Hope this helped you out! :-)
Answer: False
Explanation:
In chemical reactions new substances are formed.
Answer:
See explanation
Explanation:
When an a heavy object and a light object are thrown down from the same height, the two objects are expected to hit the ground at the same time since the two objects are both accelerated to the same extent (approximately 10m/s^2) under gravity.
However, due to air resistance, the heavier object reaches the ground first before the lighter object.
Hence, when we drop a feather and a stone at the same time from a height the stone will hit the ground faster than the feather.
Answer:
...<em>when</em><em> </em><em>the</em><em> </em><em>pressure</em><em> </em><em>is</em><em> </em><em>high</em><em> </em><em>the</em><em> </em><em>equilibrium</em><em> </em><em>increases</em><em> </em><em>but</em><em> </em><em>when</em><em> </em><em>its</em><em> </em><em>low</em><em> </em><em>equilibrium</em><em> </em><em>decreases</em><em> </em><em>also</em><em> </em><em>in</em><em> </em><em>temperature</em><em> </em><em>the</em><em> </em><em>higher</em><em> </em><em>the</em><em> </em><em>temperature</em><em> </em><em>the</em><em> </em><em>high</em><em> </em><em>the</em><em> </em><em>equilibrium</em><em> </em><em>and</em><em> </em><em>viceversa</em><em> </em><em>is</em><em> </em><em>true</em><em> </em><em>but</em><em> </em><em>also</em><em> </em><em>in</em><em> </em><em>concentration</em><em> </em><em>its</em><em> </em><em>the</em><em> </em><em>same</em><em> </em><em>case</em>