1. 4x - 8 + 2x + (-5x) + x^2 - 3 = 4x - 8 + 2x - 5x + x^2 - 3...now, we just combine like terms....lets group them...it will be easier ...x^2 + (4x + 2x - 5x ) - 8 - 3 = x^2 + x - 11
2. 2x + 5x = 8x
3. 2r + 4 + 3x - 2 = 3x + 2r + (4 - 2) = 3x + 2r + 2
4. 3x - 2y - x + 5y = (3x - x) + (5y - 2y) = 2x + 3y
5. 2y^2 - 8y^3 + 5y - 5y^2 + 4y^3 = (4y^3 - 8y^3) + (2y^2 - 5y^2) + 5y =
-4y^3 - 3y^2 + 5y
It would be C because a coefficient is always with a variable and 6 is with a variable which makes it a coefficient
Hope this helps
Have a great day/night
Note: Let us consider, we need to find the
and
.
Given:
In the given figure, BD is the angle bisector of ABC.
To find:
The
and
.
Solution:
BD is the angle bisector of ABC. So,




Divide both sides by 2.


Now,



And,





Therefore,
and
.
X-13y is the answer to that equation
Please find the attachment for a better understanding of the explanation to this question.
As we can see from the diagram attached, the X axis represented by XX' and the Y axis represented by YY' intersect each other at the origin represented by O. Further, we notice that this intersection is at the angle 90 degrees or in other words the intersection is perpendicular. Thus, we have seen that the the x and y axes in the xy plane intersect perpendicularly. And hence, the answer is TRUE.
Please note that this is always the case and this is also known as orthogonality.