Answer: The response that is expected when it broadcast an ARP request is one or zero.
Explanation: ARP request means Address Resolution Protocol which is a protocol responsible for the mapping of the IP(Internet protocol)address of a system to the MAC(Media Access Control) layer. Only one response is received only if the IP address is present in the ARP otherwise if the IP address does not matches then no response is returned.Thus only one or zero response can be received when a ARP request is process.
Answer:
MS access objects help the user list , information and designed reports .
Explanation:
MS access objects are create a forms, data base, tables,queries, and modules. There are many objects are following:-Tables, Forms,Reports, Queries.
Table:- These are objects used into a define and store the data,tables are contain the columns and the store of different data.
Form:- Form is the object that designed by the data input and control application queries or tables, forms are used in viewing records.
Reports:- Reports are the designed to the printing and calculating data,reports are used because data in read to easy format.
Queries:- Queries are provides that data from one or more table,you can define the update ,delete, insert, select data.
The answer will be C
As she is about to leave the position, in account of professionalism, she should NOT do any unnecessary harm to the current company, and she should notify the company for necessary description before leaving.
1.)
<span>((i <= n) && (a[i] == 0)) || (((i >= n) && (a[i-1] == 0))) </span>
<span>The expression will be true IF the first part is true, or if the first part is false and the second part is true. This is because || uses "short circuit" evaluation. If the first term is true, then the second term is *never even evaluated*. </span>
<span>For || the expression is true if *either* part is true, and for && the expression is true only if *both* parts are true. </span>
<span>a.) (i <= n) || (i >= n) </span>
<span>This means that either, or both, of these terms is true. This isn't sufficient to make the original term true. </span>
<span>b.) (a[i] == 0) && (a[i-1] == 0) </span>
<span>This means that both of these terms are true. We substitute. </span>
<span>((i <= n) && true) || (((i >= n) && true)) </span>
<span>Remember that && is true only if both parts are true. So if you have x && true, then the truth depends entirely on x. Thus x && true is the same as just x. The above predicate reduces to: </span>
<span>(i <= n) || (i >= n) </span>
<span>This is clearly always true. </span>
