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nikitadnepr [17]
3 years ago
12

If we need to manage a contiguous range of memory, handling requests to allocate various sized chunks, and later make those chun

ks free for reuse (as the malloc() and free() routines do in a C program), we have a number of linked list allocation algorithms that we could choose from. If our primary objective in allocating a chunk was to leave the smallest fragment possible after the allocation, which algorithm would we implement?a. slab allocator.b. worst-fit allocator.c. first-fit allocator.d. best-fit allocator.e. bit-map allocator.
Computers and Technology
1 answer:
puteri [66]3 years ago
3 0

Answer:

brst fyr aligarotr

Explanation:

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The subnet mask can be utilized to segment the 172.16.0.0 network to qualify for a minimum of 6 subnets while maximizing the numeral of broadcasters per subnet is 255.255.224.0

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2 years ago
SOMEONE PLEASE HELP ME I REPOSTED THIS 3 time and no ONE HAD HELPED ME
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The answer is B

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One or more access points positioned on a ceiling, wall, or other strategic spot in a public place to provide maximum wireless c
Lera25 [3.4K]

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hotspots.

Explanation:

Hotspots is a small geographical location with at least one access point in an outdoor/indoor setting, that provide people with maximum wireless coverage within that area and its mostly uses a wireless local-area network (WLAN) using a router to connect to an Internet service provider.

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To view the contents of a file that was compressed with the bzip2 utility, you must used the ____________________ command.
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zcat

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8 0
3 years ago
Remove gray from RGB Summary: Given integer values for red, green, and blue, subtract the gray from each value. Computers repres
sergejj [24]

Answer:  

Here is the C++ program:  

#include <iostream>   //to use input output functions    

using namespace std;   //to identify objects cin cout    

int main() {   //start of main method    

int red,green,blue,smallest;   //declare variables to store integer values of red,green, blue and to store the smallest value    

cout<<"Enter value for red: ";  //prompts user to enter value for red    

cin>>red;  //reads value for red from user    

cout<<"Enter value for green: ";  //prompts user to enter value for green  

cin>>green; //reads value for green from user    

cout<<"Enter value for blue: "; //prompts user to enter value for blue    

cin>>blue;   //reads value for blue from user    

//computes the smallest value  

if(red<green && red<blue) //if red value is less than green and blue values    

smallest=red;   //red is the smallest so assign value of red to smallest    

else if(green<blue)   //if green value is less than blue value    

smallest=green; //green is the smallest so assign value of green to smallest  

else //this means blue is the smallest    

smallest=blue;  //assign value of blue to smallest    

//removes gray part by subtracting smallest from rgb  

red=red-smallest; //subtract smallest from red    

green=green-smallest; //subtract smallest from green    

blue=blue-smallest; //subtract smallest from blue    

cout<<"red after removing gray part: "<<red<<endl;  //displays amount of red after removing gray    

cout<<"green after removing gray part: "<<green<<endl; //displays amount of green after removing gray  

cout<<"blue after removing gray part: "<<blue<<endl;  } //displays amount of blue after removing gray  

Explanation:  

I will explain the program using an example.    

Lets say user enter 130 as value for red, 50 for green and 130 for blue. So  

red = 130    

green = 50

blue = 130  

First if condition if(red<green && red<blue)   checks if value of red is less than green and blue. Since red=130 so this condition evaluate to false and the program moves to the else if part else if(green<blue) which checks if green is less than blue. This condition evaluates to true as green=50 and blue = 130 so green is less than blue. Hence the body of this else if executes which has the statement: smallest=green;  so the smallest it set to green value.    

smallest = 50    

Now the statement: red=red-smallest; becomes:    

red = 130 - 50    

red = 80    

the statement: green=green-smallest;  becomes:    

green = 50 - 50    

green = 0    

the statement: blue=blue-smallest; becomes:    

blue = 130 - 50    

blue = 80    

So the output of the entire program is:    

red after removing gray part: 80                                                                                                 green after removing gray part: 0                                                                                                blue after removing gray part: 80    

The screenshot of the program along with its output is attached.

5 0
3 years ago
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