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Lunna [17]
3 years ago
14

What gives an atom its charge?

Physics
2 answers:
s344n2d4d5 [400]3 years ago
5 0
An atom<span> with a neutral </span>charge<span> is one where the number of electrons is equal to the </span>atomic<span> number

hope i helped</span>
givi [52]3 years ago
4 0
<span>A Neutral, stable atom has no charge as it has an equal number of Protons and Electrons. An Atom gains a charge by the loss or gain of electrons thus becoming an Ion. The loss of 1 or more electrons will give the atom a Positive charge (now having more Protons then Neutrons) and becomes a Positive Ion (or Cation).  hope that helped</span>
You might be interested in
When vibrational motion in an object increases, which is a true statement?
ss7ja [257]
Hello friend!!

We know that kinetic energy is the energy possessed due to the motion of the object. And we know if the object is in a fast motion then the temperature would be high, whereas if the object is slow in motion then it will have lower temperature. So we know that the kinetic energy is indirectly related to temperature.From our knowledge we can conclude that HIGHER THE TEMPERATURE, HIGHER THE KINETIC ENERGY and LOWER THE TEMPERATURE, LOWER THE KINETIC ENERGY.
Hence, the answer to your question here is,a.kinetic energy, temperature, and thermal energy increase. 
Hope it helps!!All the best!!
5 0
3 years ago
An ore sample weighs 17.50 N in air. When the sample
zysi [14]

Answer with Explanation:

We are given that

Weight of an ore sample=17.5 N

Tension in the cord=11.2 N

We have to find the total volume and the density of the sample.

We know that

Tension, T=W-F_b

F_b=buoyancy force

T=Tension force

W=Weight

By using the formula

11.2=17.5-F_b

F_b=17.5-11.2=6.3 N

F_b=V_{object}\times \rho_{water}\cdot g

Where

V_{object}=Volume of object

\rho_{water}=1000 kgm^{-3}=Density of water

g=9.8 ms^{-2}=Acceleration due to gravity

Substitute the values then we get

6.3=9.8\times 1000\times V_{object}

V_{object}=\frac{6.3}{9.8\times 1000}=6.43\times 10^{-4} m^3

Volume of sample=6.43\times 10^{-4} m^3

Density of sample,\rho_{object}=\frac{Mass}{volume_{object}}

Where mass of ore sample=1.79 kg

Substitute the values then, we get

\rho_{object}=\frac{1.79}{6.43\times 10^{-4}}=2.78\times 10^3 kg/m^3

Density of the sample=2.78\times 10^{3} kgm^{-3}

7 0
3 years ago
What s the rate of acceleration of gravity?​
Ivenika [448]
The numerical value for the acceleration of gravity is most accurately known as 9.8 m/s/s.
4 0
3 years ago
Read 2 more answers
17. A distance-time graph indicates that an object moves 120 meters in 5 seconds and then remains at rest for 5 seconds. What is
irina1246 [14]

Answer:

12 m/s

Explanation:

Speed is distance moved per unit time and expressed as

S=d/t

S is speed, d is distance and t is time.

When at rest for five minutes, distance moved is zero hence speed is 0/5=0 m/s

When having moved 120 m for 5 s then speed is

S=120/5=24 m/s

Average speed is the average of these two speeda

Average speed=(24+0)÷2=24/2=12 m/s

Therefore, average speed is 12 m/s

3 0
3 years ago
A 1 170.0 kg car traveling initially with a speed of 25.000 m/s in an easterly direction crashes into the back of a 9 800.0 kg t
kykrilka [37]

Explanation:

It is given that,

Mas of the car, m_1=1170\ kg

Initial speed of the car, u_1=25\ m/s

Mass of the truck, m_2=9800\ kg

Initial speed of the car, u_2=20\ m/s

Final speed of the car, v_1=18\ m/s

(a) It is a case of elastic collision. Let v_2 is the final velocity of the truck right after the collision. Using the conservation of linear momentum to find it :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

v_2=\dfrac{m_1u_1+m_2u_2-m_1v_1}{m_2}

v_2=\dfrac{1170\times 25+9800\times 20-1170\times 18}{9800}

v_2=20.83\ m/s

(b) Initial kinetic energy is given by :

k_i=\dfrac{1}{2}(m_1u_1^2+m_2u_2^2)

k_i=\dfrac{1}{2}\times (1170\times (25)^2+9800\times (20)^2)

k_i=2325625\ J

Final kinetic energy is given by :

k_f=\dfrac{1}{2}(m_1v_1^2+m_2v_2^2)

k_f=\dfrac{1}{2}\times (1170\times (18)^2+9800\times (20.83)^2)

k_f=2315595.61\ J

The change in mechanical energy of the car truck system in the collision:

\Delta K=k_f-k_i

\Delta K=2315595.61-2325625

\Delta k=-10029.39\ J

The loss in kinetic energy is 10029.39 Joules.

(c) The change in mechanical energy gets changed energy gets changed in the form of heat and light.

Hence, this is the required solution.

6 0
3 years ago
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