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blsea [12.9K]
3 years ago
9

A student conducts an experiment in which a cart is pulled by a variable applied force during a 2 s time interval. In trial 1, t

he student exerts the force on a cart of mass M. In trial 2, the student exerts the force on a cart of mass 3M. In trial 3, the student exerts the force on a cart of 5M. In which trial will the cart experience the greatest change in momentum from 0 s to 2 s?
Physics
1 answer:
fredd [130]3 years ago
5 0

Answer:

The answer is "Including all three studies of 0s to 2s, that shift in momentum is equal".

Explanation:

Its shift in momentum doesn't really depend on the magnitude of its cars since the forces or time are similar throughout all vehicles.

Let's look at the speed of the car

F = m a\\\\a =\frac{F}{m}

We use movies and find lips

\to v = v_0 + a t\\\\\to v = v_0 + (\frac{F}{m}) t

The moment is defined by

\to p = m v

The moment change

\Delta p = m v - m v_0

Let's replace the speeds in this equation

\Delta p = m (v_0 + \frac{F}{m t}) - m v_0\\\\\Delta p = m v_0  + F t - m v_0\\\\\Delta p = F t

They see that shift is not directly proportional to the mass of cars since the force and time were the same across all cars.

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The answer is -i, trust me.

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3 years ago
A 20 ohm resistor has 210 volts measured<br> across it. What is the current?
AlexFokin [52]

Answer:

Given =

Resistance = 20 ohm

Volt = 210 volts

Solution =

By Ohm's Law

R = V/I

I = V/R

I = 210/20

I = 11.5 ampere. Answer

3 0
3 years ago
A body weighs 10newton in air and 9.5 in water. How will it weigh in alchohol if density 0.8gcm-³​
Katen [24]

Answer:

The weight of object in alcohol is, W₀ = 9.6 N

Explanation:

Given,

The weight of body in air, Wₐ = 10 N

The weight of the body in water, Wₓ = 9.5 N

The density of the alcohol, ρ = 0.8 g/cm³

                                                = 800 kg/m³

The weight of body in water = weight of object in air - weight of water displaced

                        9.5 N = 10 N - weight of water displaced

                       Weight of water displaced = 0.5 N

The mass of the displaced water, m = 0.5 / 9.8

                                                            = 0.051 kg

Therefore the volume of the water displaced,

                                              V = m / ρ

                                                  = 0.051 / 1000

                                                   = 5.1 x 10⁻⁵ m³

<em>The volume of water displaced is equal to the volume of alcohol displaced</em>

Therefore, the mass of the alcohol displaced, = V x ρ

                                                                             = 5.1 x 10⁻⁵ x 800

                                                                             = 0.0405 kg

The weight of the alcohol displaced, w = 0.0405 x 9.8

                                                                    = 0.4 N

Therefore,

The weight of body in alcohol = weight of object in air - weight of alcohol displaced

                             W₀ = W - w

                                    = 10 N - 0.4 N

                                     = 9.6 N

Hence, the weight of object in alcohol is, W₀ = 9.6 N

4 0
3 years ago
5. What is the density of 4.5 mL of a liquid that has a mass of 1.3 grams?
antoniya [11.8K]

Answer:

A. 0.289g/mL

Explanation:

Using the equation for density which is d = m/v  or density = mass/volume, we input 1.3g/4.5mL and get 0.289g/mL.

5 0
3 years ago
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Correct answer choice is :



B) Able to travel through a vacuum.



Explanation:



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Read more on Brainly.com - brainly.com/question/1697984#readmore

4 0
3 years ago
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