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2 years ago

How much mass would pizza dough have after you flatten it

Physics

2 answers:

mars1129 [50]2 years ago

3 0

Answer:

the answer is that the dough has the same mass before and after it was flattened

Kamila [148]2 years ago

3 0

Answer:

it has the same amount of mass because you haven't taken anything away or added anything to it

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A large, cylindrical water tank with diameter 3.60 m is on a platform 2.00 m above the ground. The vertical tank is open to the

zysi [14]

To solve this problem it is necessary to apply the concepts related to the geometry of a cylindrical tank and its respective definition.

The volume of a tank is given by

$V = \frac{\pi d^2}{4}h$

Where

d = Diameter

h = Height

Considering that there are two stages, let's define the initial and final volume as,

$V_0 = \frac{\pi d^2}{4}H$

$V_f = \frac{\pi d^2}{4}h$

We know as well by definition that

$1gal = 3.785*10^{-3}m^3$

Then we have for the statement that

$V_f = V_0 -1gal$

$V_f = V_0 - 3.785*10^{-3}$

Replacing the previous data

$\frac{\pi d^2}{4}h = \frac{\pi d^2}{4}H- 3.785*10^{-3}$

$\frac{\pi (3.6)^2}{4}h = \frac{\pi (3.6)^2}{4}(2)- 3.785*10^{-3}$

Solving to get h,

$h = 1.99963m$

Therefore the change is

$\Delta h = H-h$

$\Delta h = 2- 1.99963$

$\Delta h = 3.7*10^{-4}m=0.37mm$

Therefore te change in the height of the water in the tank is 0.37mm

4 0

3 years ago

A toaster draws 8 A of current with a voltage of 120 V. Which is the power used by the toaster?

dexar [7]

$U=120 \text{ V}\\
I=8\text{ A}\\
P=U\cdot I\\\\
P=120\cdot8=960 \text{ W}
$

7 0

3 years ago

A cylindrical container closed of both end has a radius of 7cm and height of 6cm A.)find the total surface area of the container

Natalka [10]

Given:

A cylindrical container closed of both end has a radius of 7cm and height of 6cm.

Explanation:

A.) Find the total surface area of the container.

A = 2πrh + 2πr²
A = 2(3.14)(7)(6) + 2(3.14)(7 × 7)
A = 263.76 + 307.72
A = 571.48

B.) Find the volume of the container.

V = πr²h
V = (3.14)(7×7)(6)
V = 923.16

Not sure huhuness.

#CarryOnLearning

8 0

3 years ago

Read 2 more answers

A 30-mm-diameter copper rod is 1 m long with a yield strength of 70 MPa. Determine the axial force necessary to cause the diamet

ivolga24 [154]

Explanation:

Given data:

d = 30 mm = 0.03 m

L = 1m

S $_{y}$ = 70 Mpa

Δd = -0.0001d

Axial force = ?

validity of elastic deformation assumption.

Solution:

O'₂ = Δd/d = (-0.0001d)/d = -0.0001

For copper,

v = 0.326 E = 119×10³ Mpa

O'₁ = O'₂/v = (-0.0001)/0.326 = 306×10⁶

∵δ = F.L/E.A and σ = F/A so,

σ = δ.E/L = O'₁ .E = (306×10⁻⁶).(119×10³) = 36.5 MPa

F = σ . A = (36.5 × 10⁻⁶) . (π/4 × (0.03)²) = 25800 KN

S $_{y}$ = 70 MPa > σ = 36.5 MPa

∵ elastic deformation assumption is valid.

so the answer is

F = 25800 K N and S $_{y}$ > σ

3 0

3 years ago

You walk to school every day. It is 0.5 miles. After school you walk to Kroger, which is 1.3 miles. You leave Kroger to go all b

marin [14]

The total distance you haved walked should be 2.6 miles

7 0

3 years ago