0.985 rounded to the nearest tenth

1 answer:

8 0

They always try to trick you with this. Remember anything 5 or above would round up, anything 4 and under would round down. So look for the tenth place. that's the 9. The number to the right is 8 which is greater than 5. That means round up. You can't round it to 0.1 because that takes it back down. So you just move it over. The answer is 1.0.

You might be interested in

On a coordinate plane, a dashed straight line has a positive slope and goes through (negative 3, 1) and (0, 3). Everything to th

miss Akunina [59]

Answer:

$y> \frac{2}{3}x+3$

Step-by-step explanation:

we have the points

(-3,1) and (0,3)

step 1

Find the slope m of the line

The formula to calculate the slope between two points is equal to

$m=\frac{y2-y1}{x2-x1}$

substitute the values

$m=\frac{3-1}{0+3}$

$m=\frac{2}{3}$

step 2

Find the equation of the line in slope intercept form

$y=mx+b$

we have

$m=\frac{2}{3}$

$b=3$ ----> the y-intercept is the point (0,3)

substitute the values

$y=\frac{2}{3}x+3$

step 3

Find the equation of the inequality

we know that

The slope is positive

Everything to the left of the line is shaded ( The inequality is of the form y > ax+b or y ≥ ax+b)

Is a dashed line (The inequality is of the form y > ax+ b or y < ax+b)

therefore

The equation of the inequality is of the form y > ax+b

The inequality is

$y> \frac{2}{3}x+3$

see the attached figure to better understand the problem

4 0

3 years ago

Read 2 more answers

Product of two natural numbers p and q is 590 and their hcf is 59. how many set of values of p and q is possible

djverab [1.8K]

$\text{Let the product of two natural numbers p and q is 590, and their HCF is 59}\\
\\
\text{we know that the product of LCM and HCF of any two numbers is equal}\\
\text{to the product of the numbers. that is}\\
\\
\text{HCF}\times \text{ LCM}=p\times q\\
\\
\Rightarrow 59 \times \text{LCM}=590\\
\\
\Rightarrow \text{LCM}=\frac{590}{59}\\
\\
\Rightarrow \text{LCM}=10\\
\\
\text{for any two natural numbers, their Least Common Multiple (LCM) is always}$