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adelina 88 [10]
3 years ago
13

Plssss help me its urgent:(

Mathematics
1 answer:
Dafna11 [192]3 years ago
8 0

according to my calculations 4 if its wrong sorry bro

Step-by-step explanation:

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A teacher’s monthly gross pay is $5,321. The federal government withholds 15% of the teacher’s monthly gross pay for income taxe
lubasha [3.4K]

Answer:

798.15

Step-by-step explanation:

heres a neat trick you can do instead of doing that long process to get 15% of 5321 just use a calculator and do 5321 x .15

3 0
3 years ago
A clothes inspector examines 75 randomly chosen garments a day. If 10 of them have a defect, about how many garments are defecti
Nookie1986 [14]
950 garments would be defective
8 0
3 years ago
↓↓ASAP PLAS HELP WILL GIVE BRAINLYEST WILL GIVE BRAINLYEST↓↓
Stels [109]

we know that

diameter of the base of a cylindrical can= 4 in----------> r=2 in

h=6.5 in

[surface area]=2*[pi*r²]+[2*pi*r*h]

then

[surface area]=2*[pi*2²]+[2*pi*2*6.5]=[ 25.13 ]+[ 81.68 ]=106.81 in²

the answer is 106.8 in²

3 0
3 years ago
What is the circumference of a 12 inch diameter pizza answer in terms of pi
Sedbober [7]
Answer: 37.69911 in. (Round if necessary)

Steps:
2πr
2·π·6 = 37.69911


8 0
3 years ago
Read 2 more answers
Find the area under the curve y = 13/x3 from x = 1 to x = t. Evaluate the area under the curve for t = 10, t = 100, and t = 1000
zvonat [6]

Answer:

t = 10

A = 32496.75

t = 100

A = 324999996.8

t = 1000

A=3.25\times 10^{12}

Step-by-step explanation:

The area under the curve is calculated by using the following definite integral:

A = \int\limits^t_ {1} \,{13\cdot x^{3}}  dx

A = 13 \int\limits^t_1 {x^{3}} \, dx

A = \frac{13}{4}\cdot (t^{4}-1)

Evaluated areas are presented below:

t = 10

A = 32496.75

t = 100

A = 324999996.8

t = 1000

A=3.25\times 10^{12}

8 0
3 years ago
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