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2 years ago

Which undefined terms are needed to define parallel lines

2 answers:

5 0

First off, Parallel lines are two lines that lie within the same plane and never intersect, So the undefined terms that are needed to define a parallel line are Lines, planes.

BigorU [14]2 years ago

5 0

The undefined terms are needed to define parallel lines are coplanar and line. Parallel lines are coplanar lines that do not intersect.

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Find the missing angle.

Vika [28.1K]

Answer:

X = 45

Step-by-step explanation:

Hope it will be helpful for you.

8 0

2 years ago

Write the equation of a line passing through the points (2, -4) and (2, -9). Write the equation in slope-intercept form.

Norma-Jean [14]

1. find our slope: y2 - y1/ x2- x 1

-9 + 4= -5
2 - 2 = 0

m = 0

2. now we need to use our point-slope form to find our y intercept

point-slope form: y - y1 = m(x - x1)

y + 4 = 0(x - 2)

distribute:
y + 4 = 0x

3. get y by itself

y + 4 - 4 = y
0x - 4 = 0x - 4

4. write in slope-intercept form:

y = 0x - 4
OR
y = -4

8 0

3 years ago

John and his friend ordered lunch at a local sandwich shop. They each ordered a soft drink that costs $1.65. John orders a whole

ExtremeBDS [4]

Answer:

a. $12.54 = $ 1.65 + c/2 + c b. $ 7.26

Step-by-step explanation:

a. What equation can you use to find the cost c of a sandwich

Let c be the cost of a whole ham sandwich. Now, the total bill = cost of drinks + cost of half a ham sandwich + cost of a whole ham sandwich.

total bill = $ 12.54, cost of drinks = $ 1.65, cost of half a ham sandwich = c/2 and cost of a whole ham sandwich = c. So,

$12.54 = $ 1.65 + c/2 + c

b. What is the value of c

We then solve for c in the equation $12.54 = $ 1.65 + c/2 + c

collecting like terms, we have

$12.54 - $ 1.65 = c/2 + c

$ 10.89 = 3c/2

multiplying through by 2, we have

$ 10.89 × 2 = 3c

$ 21.78 = 3c

dividing through by 3, we have

c = $ 21.78/3

= $ 7.26

4 0

2 years ago

Given f'(x)=(x-4)(6-2x) find the x-coordinate for the relative minimum of the graph f(x).

vlabodo [156]

The graph you plotted is the graph of f ' (x) and NOT f(x) itself. 

Draw a number line. On the number line plot x = 3 and x = 4. These values make f ' (x) equal to zero. Pick a value to the left of x = 3, say x = 0. Plug in x = 0 into the derivative function to get

f ' (x) = (x-4)(6-2x)
f ' (0) = (0-4)(6-2*0)
f ' (0) = -24

So the function is decreasing on the interval to the left of x = 3. Now plug in a value between 3 and 4, say x = 3.5

f ' (x) = (x-4)(6-2x)
f ' (3.5) = (3.5-4)(6-2*3.5)
f ' (3.5) = 0.5

The function is increasing on the interval 3 < x < 4. The junction where it changes from decreasing to increasing is at x = 3. This is where the min happens.

So the final answer is C) 3

5 0

3 years ago

The least common multiple of two numbers is 60, and one of the numbers is 7 less than the other number. What are the numbers?

storchak [24]

Step One - List the factors of 60.
Step Two - Locate the factors that are seven apart from each other.

Factors of 60:
1 × 60
2 × 30
3 × 20
4 × 15
5 × 12
6 × 10

60 - 1 = 59
30 - 2 = 28
20 - 3 = 17
15 - 4 = 11
12 - 5 = 7
10 - 6 = 4

5 is 7 less than 12, and 60 is their least common multiple.

Answer: 5 and 12

8 0

3 years ago