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FinnZ [79.3K]
3 years ago
9

Which undefined terms are needed to define parallel lines

Mathematics
2 answers:
Assoli18 [71]3 years ago
5 0

First off, Parallel lines are two lines that lie within the same plane and never intersect, So the undefined terms that are needed to define a parallel line are Lines, planes.

BigorU [14]3 years ago
5 0
The undefined terms are needed to define parallel lines are coplanar and line. Parallel lines are coplanar lines that do not intersect.
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AnsWER:

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Step-by-step explanation:

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I think it would be 5/8
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8 0
3 years ago
Can someone answer question 2a and b only please
Mice21 [21]

Answer:

2a)  -2

b) 8

Step-by-step explanation:

<u>Equation of a parabola in vertex form</u>

f(x) = a(x - h)² + k

where (h, k) is the vertex and the axis of symmetry is x = h

2 a)

Using the equation of a parabola in vertex form, a parabola with vertex (2, -6):  

f(x) = a(x - 2)² - 6

If one of the x-axis intercepts is 6, then

                 f(6) = 0

⇒ a(6 - 2)² - 6 = 0

⇒         16a - 6 = 0

⇒              16a = 6

⇒                  a = 6/16 = 3/8

So f(x) = 3/8(x - 2)² - 6

To find the other intercept, set f(x) = 0 and solve for x:

                    f(x) = 0

⇒ 3/8(x - 2)² - 6 = 0

⇒      3/8(x - 2)² = 6

⇒           (x - 2)² = 16

⇒              x - 2 = ±4

⇒                   x = 6,  -2

Therefore, the other x-axis intercept is -2

b)

Using the equation of a parabola in vertex form, a parabola with vertex (2, -6):  

f(x) = a(x - 2)² - 6

If one of the x-axis intercepts is -4, then

                 f(-4) = 0

⇒ a(-4 - 2)² - 6 = 0

⇒         36a - 6 = 0

⇒              36a = 6

⇒                  a = 6/36 = 1/6

So f(x) = 1/6(x - 2)² - 6

To find the other intercept, set f(x) = 0 and solve for x:

                    f(x) = 0

⇒  1/6(x - 2)² - 6 = 0

⇒       1/6(x - 2)² = 6

⇒           (x - 2)² = 36

⇒              x - 2 = ±6

⇒                   x = 8,  -4

Therefore, the other x-axis intercept is 8

8 0
2 years ago
Answer please, thanks.
Rudik [331]
A) The perimeter is the length around the rectangle, so it would be 2 + 5 + 2 + 5 = 14m

The area is 2m * 5m = 10m^2

b/c) You have to draw a rectangle with a perimeter of 14m, and an area that ISN'T 10m^2. You could draw a 3m by 4m rectangle which would have a perimeter of 14m and an area of 12m^2.
4 0
3 years ago
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