The value of c such that the function f is a probability density function is 2
<h3>How to determine the value of c?</h3>
The density function is given as:
f(x) = cxe^(−x^2) if x ≥ 0
f(x) = 0 if x < 0.
We start by integrating the function f(x)
∫f(x) = 1
This gives
∫ cxe^(−x^2) = 1
Next, we integrate the function using a graphing calculator.
From the graphing calculator, we have:
c/2 * (0 + 1) = 1
Evaluate the sum
c/2 * 1 = 1
Evaluate the product
c/2 = 1
Multiply both sides of the equation by 2
c = 2
Hence, the value of c such that the function f is a probability density function is 2
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Answer:
I think Prism b
Step-by-step explanation:
If you add the numbers up prism b is 17 and prism a is 16. I hope this helped
Answer:
(f o f^-1 (10)) = 10
Step-by-step explanation:
f ^ -1 = (x + 10)/10
from solving from f(x) = 10x - 10
since 10x - 10 is a one-to-one function it has an inverse
so f o f^-1 (x) = x
(f o f^-1 (10)) = 10
6 times 8…………zzzzzzzzzzzzzzzzz