Mean weight of the bag of pears = u = 8 pounds
Standard deviation = s = 0.5 pounds
We have to find what percentage of bags of pears will weigh more than 8.25 pounds. This can be done using the z score.
We have to convert x = 8.25 to z scores, which will be:
z score = 0.5From the z table, the probability of z score being greater than 0.5 is 0.3085
Therefore, the probability of a bag to weigh more than 8.25 pounds is 0.3085
Thus 0.3085 or 31% (rounded to nearest integer) of bags of pears will have weight more than 8.25 pounds at the local market.
Answer: 3312q^2 - 9093q + 5914
Step-by-step-explanation:
Answer:
1
Step-by-step explanation:
Range is when you subtract the greatest to smallest.
So
3-2=1
The probability of the message lasting longer than six minutes is 0.955. I hope this helps!