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Gennadij [26K]
3 years ago
10

What is the surface area of the box if it is scaled up by a factor of 10? The surface area is: 736 cm. Lenght: 12 cm. Width: 4 c

m. Height: 20 cm.
Mathematics
1 answer:
grandymaker [24]3 years ago
6 0

739*12*4*20=71,000 divded by 2=36,000

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What are the factors of 7x + 5x + 12 + 23
emmainna [20.7K]

Answer:

7, x, 5, and x

Step-by-step explanation:

factors are numbers or variables being multiplied by something else. 12 and 23 arent being multiplied by anything

4 0
3 years ago
A manufacturing company regularly conducts quality control checks at specified periods on the products it manufactures. Historic
Rina8888 [55]

Answer:

The probability that none of the LED light bulbs are​ defective is 0.7374.

Step-by-step explanation:

The complete question is:

What is the probability that none of the LED light bulbs are​ defective?

Solution:

Let the random variable <em>X</em> represent the number of defective LED light bulbs.

The probability of a LED light bulb being defective is, P (X) = <em>p</em> = 0.03.

A random sample of <em>n</em> = 10 LED light bulbs is selected.

The event of a specific LED light bulb being defective is independent of the other bulbs.

The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 10 and <em>p</em> = 0.03.

The probability mass function of <em>X</em> is:

P(X=x)={10\choose x}(0.03)^{x}(1-0.03)^{10-x};\ x=0,1,2,3...

Compute the probability that none of the LED light bulbs are​ defective as follows:

P(X=0)={10\choose 0}(0.03)^{0}(1-0.03)^{10-0}

                =1\times 1\times 0.737424\\=0.737424\\\approx 0.7374

Thus, the probability that none of the LED light bulbs are​ defective is 0.7374.

6 0
3 years ago
Janice is training for a 5K. She predicted she would spend 90 minutes running this week. She actually ran for a total of 120 min
Levart [38]
I agree with the other person that this is 25% error
4 0
3 years ago
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What is the slope of the line?<br> y + 5 = 2(x + 1)<br><br> A. 1/5<br> B. 2/5<br> C. 2<br> D. 1/2
Zinaida [17]

Answer:

it's 2

Step-by-step explanation:

hope this helps you.

7 0
2 years ago
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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar. Chris is playing a
alisha [4.7K]

Let's call the aces h, d, c, s for hearts, diamonds, clubs and spades. So, h, d are red and [ted] c, s[/tex] are black.

Since the first card is replaced, the two picks are identical. This means that the sample space is given by all the possible couple

(x,y)\, x, y \in \{h,d,c,s\}

There are 16 such couples (we have four choices for the first card, and the same four choices for the second card). Now let's compute the odds in our favour to deduce the probability of winning:

If we want a player to draw two card of the same colour, the following couples are good:

(h,h),\ (h,d),\ (d,h),\ (d,d),\ (c,c),\ (c,s),\ (s,c),\ (s,s)

so 8 possible couples over 16. This means that the probability that a player draws two cards of the same color is 8/16 = 1/2.

Similarly, the probability of drawing a red ace first and then a black ace is represented by the following couples:

(h,c),\ (h,s),\ (d,c),\ (d,s)

which are 4 over the same 16 as above, thus leading to a probability of 4/16 = 1/4.

4 0
3 years ago
Read 2 more answers
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