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sesenic [268]
3 years ago
7

Suppose that profit for a particular product is calculated using the linear equation: Profit = 20S + 3D. Which of the following

combinations of S and D would yield a maximum profit?
a. S = 0, D = 0
b. S = 405, D = 0
c. S = 0, D = 299
d. S = 182, D = 145
Mathematics
1 answer:
uranmaximum [27]3 years ago
7 0

Answer:

b. S = 405, D = 0

Step-by-step explanation:

We have been given that profit for a particular product is calculated using the linear equation: \text{Profit}=20S+3D. We are asked to choose the combinations of S and D that would yield a maximum profit.

To solve our given problem, we will substitute given values of S and D in the profit function one by one.

a. S = 0, D = 0

\text{Profit}=20S+3D

\text{Profit}=20(0)+3(0)

\text{Profit}=0

b. S = 405, D = 0

\text{Profit}=20S+3D

\text{Profit}=20(405)+3(0)

\text{Profit}=8100+0

\text{Profit}=8100

c. S = 0, D = 299

\text{Profit}=20S+3D

\text{Profit}=20(0)+3(299)

\text{Profit}=0+897

\text{Profit}=897

d. S = 182, D = 145

\text{Profit}=20S+3D

\text{Profit}=20(182)+3(145)

\text{Profit}=3640+435

\text{Profit}=4075

Since the combination S = 405, D = 0 gives the maximum profit ($8100), therefore, option 'b' is the correct choice.

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