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3 years ago

Select all that are measures of angles coterminal with a 145° angle.

Mathematics

2 answers:

Mamont248 [21]3 years ago

3 0

The first 2 and last 2. I just did this assignment

Margaret [11]3 years ago

3 0

Answer: 575°, -215°, 505° and 865°

Step-by-step explanation:

The co-terminal angle of an angle that has the common terminal to the angle,

It is defined by the formula,

A + 360 n

Where n is any integer,

Here A = 145°,

Thus, for n = 1, 2, -1 and -2

co-terminal angles are,

505°, 865°, 215° and 575° respectively.

⇒ Option first, second, seventh and eighth are the correct options.

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Find the value of the determinant using the method of expansion by minors; expand on the third row

valkas [14]

For the matrix

$\begin{bmatrix}{a_{11}} & {a_{12}} & {a_{13}} \\ {a_{21}} & {a_{22}} & {a_{23}} \\ {a_{31}} & {a_{32}} & {a_{33}}\end{bmatrix}$

the determinant using the method of expansion by minors, expanding on the third row is:

$\det \begin{bmatrix}{a_{11}} & {a_{12}} & {a_{13}} \\ {a_{21}} & {a_{22}} & {a_{23}} \\ {a_{31}} & {a_{32}} & {a_{33}}\end{bmatrix}=a_{31}\det \begin{bmatrix}{a_{12}} & {a_{13}} & {} \\ {a_{22}} & {a_{23}} & {} \\ {} & {} & {}\end{bmatrix}-a_{32}\det \begin{bmatrix}{a_{11}} & {a_{13}} & {} \\ {a_{21}} & {a_{23}} & {} \\ {} & {} & {}\end{bmatrix}+a_{33}\det \begin{bmatrix}{a_{12}} & {a_{12}} & {} \\ {a_{22}} & {a_{22}} & {} \\ {} & {} & {}\end{bmatrix}$

Answer:

First, we compute the determinants of the minors:

$\begin{gathered} \det \begin{bmatrix}{0} & {4} & {} \\ {-1} & {3} & {} \\ {} & {} & {}\end{bmatrix}=0+4=4, \\ \det \begin{bmatrix}{1} & {4} & {} \\ {1} & {3} & {} \\ {} & {} & {}\end{bmatrix}=3-4=-1, \\ \det \begin{bmatrix}{1} & {0} & {} \\ {1} & {-1} & {} \\ {} & {} & {}\end{bmatrix}=-1-0=-1. \end{gathered}$

Therefore:

$\det \begin{bmatrix}{1} & {0} & {4} \\ {1} & {-1} & {3} \\ {0} & {5} & {-2}\end{bmatrix}=0\times4-5\times(-1)+(-2)\times(-1)=5+2=7.$

3 0

1 year ago

Elliott is 63 inches tall, which is 9inches taller than cousin, Jackson.write and solve an addition equation to find Jackson hei

yulyashka [42]

Its pretty simple
63-9=54
Since Elliott is 9 inches taller than jackson, you need to subtract and thats how you get the answer

7 0

3 years ago

Solve triangle ABC. (If an answer does not exist, enter DNE. Round your answers to one decimal place. Below, enter your answers

OleMash [197]

Answer:

∠A1 = 27.4°, ∠A2 = 56.6°, ∠C1 =104.6°, ∠C2=75.4°, a1 = 79.9 and a2 = 144.9

Step-by-step explanation:

From Sine rule

$\frac{a}{sinA}=\frac{b}{sinB} = \frac{c}{sinC}$

∴ b / sinB = c / sinC

From the question,

b = 129, c = 168 and ∠B = 48°

∴ 129 / sin48° = 168 / sinC

Then, sinC = (168×sin48)/129

sinC = 0.9678

C = sin⁻¹(0.9678)

C = 75.42

∠C2=75.4°

and

∴∠C1 = 180° - 75.4°

∠C1 =104.6°

For ∠A

∠A1 = 180° - (104.6°+48°) [sum of angles in a triangle]

∠A1 = 27.4°

and

∠A2 = 180° - (75.4° + 48°)

∠A2 = 180° - (123.4°)

∠A2 = 56.6°

For side a

a1/sinA1 = b/sinB

a1/ sin27.4° = 129/sin48

a1 = (129×sin27.4°)/sin48

a1 = 79.8845

a1 = 79.9

and

a2/sinA2 = b / sinB

a2/ sin56.6° = 129/sin48

a2 = (129×sin56.6°)/sin48

a2 = 144.9184

a2 = 144.9

Hence,

∠A1 = 27.4°, ∠A2 = 56.6°, ∠C1 =104.6°, ∠C2=75.4°, a1 = 79.9 and a2 = 144.9

4 0

3 years ago

Write 13 divided by 4/7 as a multiplication expression

almond37 [142]

Answer:

13/1*7/4

Step-by-step explanation:

The way you get this is by using the Keep, Change, Flip Method. 13 as a fraction would be 13/1, and this is the keep phase. The change phase is where you change division to multiplication. The flip phase is when we flip the numerator and denominator. Remember, this only works when dividing fractions.

8 0

3 years ago

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madam [21]

Answer:

Step-by-step explanation:

1 × a = a

a² = a*a ; a³ = a*a*a .....

$(\frac{a}{b}) ^{n} = \frac{a^{n} }{b^{n} }$