Answer:
5
Step-by-step explanation:
2x5x7=70
Answer:
Hence the ground distance is about 889m between stadium and Tennis court.
Step-by-step explanation:
Given:
A pilot at height of 125 m(flying the advertising blimp)
angle of depression=8 degrees.
To find :
The ground distance stadium and tennis court.
Solution :
Using Trigonometric Function we can solve it ,
(Refer the attachment for fig)
Considering above data we get a triangle(ABC)
with point A represent pilot position and C court position and B as stadium.
The height AB=125 m
angle of depression= 8 degrees.
Using
<em>tan∅ =AB/BC</em>
tan(8)=125/BC
BC=125/tan(8)
=125/0.14054
=889.2
=889 m
Hence the ground distance is about 889m between stadium and Tennis court.
Answer:
6.32
Step-by-step explanation:
:|
Answer:
459
Step-by-step explanation:
First line:
clock showing 9 o'clock + clock showing 9 o'clock + clock showing 3 o'clock = 9 + 9 + 3 = 21
Second line:
The calculators look exactly the same.
3 * calculators = 30
1 calculator = 10
Third line:
1 bulb + 1 bulb - 1 bulb = 15
Since 1 bulb - 1 bulb = 0, we have 1 bulb + 0 = 15, or
1 bulb = 15
Last line:
Clock showing 9 o'clock = 9
Calculator = 10
3 bulbs = 3 * 15 = 45
Total = 9 + 10 * 45 = 9 + 450 = 459
Answer:
Step-by-step explanation
Hello!
Be X: SAT scores of students attending college.
The population mean is μ= 1150 and the standard deviation σ= 150
The teacher takes a sample of 25 students of his class, the resulting sample mean is 1200.
If the professor wants to test if the average SAT score is, as reported, 1150, the statistic hypotheses are:
H₀: μ = 1150
H₁: μ ≠ 1150
α: 0.05
![Z= \frac{X[bar]-Mu}{\frac{Sigma}{\sqrt{n} } } ~~N(0;1)](https://tex.z-dn.net/?f=Z%3D%20%5Cfrac%7BX%5Bbar%5D-Mu%7D%7B%5Cfrac%7BSigma%7D%7B%5Csqrt%7Bn%7D%20%7D%20%7D%20~~N%280%3B1%29)

The p-value for this test is 0.0949
Since the p-value is greater than the level of significance, the decision is to reject the null hypothesis. Then using a significance level of 5%, there is enough evidence to reject the null hypothesis, then the average SAT score of the college students is not 1150.
I hope it helps!