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yuradex [85]
3 years ago
13

Ashley was 98 pounds one year ago. If she now weighs 112 pounds, what is the percent increase in her weight?

Mathematics
2 answers:
Sever21 [200]3 years ago
5 0
B.14.2 because you subtract the 98 to the 112
Reptile [31]3 years ago
5 0
Percentage increase =
increased amount / Original amount X 100

Increased amount = 112
Original amount = 98

Percentage increase = 112/98 X 100
= 14.2.
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Mkey [24]

There are 13 cards of each suit.

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7 0
2 years ago
Several years​ ago, 50​% of parents who had children in grades​ K-12 were satisfied with the quality of education the students r
galina1969 [7]

Answer:

The 95% confidence interval for the proportion of parents that are satisfied with their children's education is (0.4118, 0.4618). 0.5 is not part of the confidence interval, so this represents evidence that​ parents' attitudes toward the quality of education have changed.

Step-by-step explanation:

We have to see if 50% = 0.5 is part of the confidence interval.

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

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For this problem, we have that:

n = 1095, \pi = \frac{478}{1095} = 0.4365

95% confidence level

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The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4365 - 1.96\sqrt{\frac{0.4365*0.5635}{1095}} = 0.4118

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4365 + 1.96\sqrt{\frac{0.4365*0.5635}{1095}} = 0.4612

The 95% confidence interval for the proportion of parents that are satisfied with their children's education is (0.4118, 0.4618). 0.5 is not part of the confidence interval, so this represents evidence that​ parents' attitudes toward the quality of education have changed.

5 0
2 years ago
(−1) to the power of 3
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(-1) ^3

-(1) * (-1) * (-1)

1 * (-1)

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3 0
3 years ago
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Inga [223]

no because like he said you have to move the decimal places



6 0
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