and
Recall:
if we have a quadratic equation, , where
,
and
are real numbers and
,
.
Given:
Solving for :
Solving with the positive value:
Solving with the negative value:
Answer:
The height of the trapezoid is 6.63 units
The perimeter of the trapezoid is 38 units
Step-by-step explanation:
Whenever a geometry problem is given, it is often useful if it is sketched out. A sketch of this problem can be found in the image attached.
A)
We can see that a right-angled triangle is formed between points BED, with line BE being the height, h.
To get the dimensions of the line EB, we subtract the dimensions of DC from AB. This will give 15 -5 = 10
hence the dimensions of the righ angled triangle are
DE= h
DB = 12 (diagonal)
EB = 10
From Pythagoras' theorem,
The height of the trapezoid is 6.63
B)
We can get the perimeter of the trapezoid by adding the dimensions of all four sides together.
This will be
AD + DC + CB + AB
However we can assume for this case that it is a symmetrical trapezoid, and hence AD = CB
Thus, perimeter =
2 (AD) + DC +AB
2(9) +5 +15 = 38.
The perimeter of the trapezoid is 38 units
