Question

Tìm x : 2x^2-7x+3=0 giúp tui zới, please

Answer 1

Solving Quadratic Equations with the Quadratic Formula

Answer:

$x = 3$ and $x = \frac{1}{2}$

Step-by-step Explanation:

Recall:

if we have a quadratic equation, $ax^2 +bx +c = 0$, where $a$, $b$ and $c$ are real numbers and $a \neq 0$, $x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}$.

Given:

$2x^2 -7x +3 = 0$

Solving for $x$:

$x = \frac{-(-7) \pm \sqrt{(-7)^2 -4(2)(3)}}{2(2)} \\ x = \frac{-(-7) \pm \sqrt{49 -4(2)(3)}}{2(2)} \\ x = \frac{7 \pm \sqrt{49 -24}}{4} \\ x = \frac{7 \pm \sqrt{25}}{4} \\ x = \frac{7 \pm 5}{4}$

Solving with the positive value:

$x = \frac{7 +5}{4} \\ x = \frac{12}{4} \\ x = 3$

Solving with the negative value:

$x = \frac{7 -5}{4} \\ x = \frac{2}{4} \\ x = \frac{1}{2}$