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Free_Kalibri [48]
3 years ago
14

Tìm x : 2x^2-7x+3=0 giúp tui zới, please

Mathematics
1 answer:
Gnoma [55]3 years ago
7 0
<h2>Solving Quadratic Equations with the Quadratic Formula</h2>

<h3>Answer:</h3>

x = 3 and x = \frac{1}{2}\\

<h3>Step-by-step Explanation: </h3>

Recall:

if we have a quadratic equation, ax^2 +bx +c = 0, where a, b and c are real numbers and a \neq 0, x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}.

Given:

2x^2 -7x +3 = 0

Solving for x:

x = \frac{-(-7) \pm \sqrt{(-7)^2 -4(2)(3)}}{2(2)} \\ x = \frac{-(-7) \pm \sqrt{49 -4(2)(3)}}{2(2)} \\ x = \frac{7 \pm  \sqrt{49 -24}}{4} \\ x = \frac{7 \pm \sqrt{25}}{4} \\ x = \frac{7 \pm 5}{4}

Solving with the positive value:

x = \frac{7 +5}{4} \\ x = \frac{12}{4} \\ x = 3

Solving with the negative value:

x = \frac{7 -5}{4} \\ x = \frac{2}{4} \\ x = \frac{1}{2}

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